It’s open circle and a line pointed left so less than of equal to 75?
y = -9
Ok so to write the equation of the line you will need the slope and y-intercept. Since we are given two-point we can easily find the slope by using this equation for slope formula:
![\frac{y_{2}-y_{1} }{x_{2}-x_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7By_%7B2%7D-y_%7B1%7D%20%20%7D%7Bx_%7B2%7D-x_%7B1%7D%20%20%7D)
So now that we have our equation we can just plug in the numbers:
![\frac{(-9)-(-9)}{5-(-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-9%29-%28-9%29%7D%7B5-%28-3%29%7D)
After subtracting you should get:
0/8
Since zero is in the numerator and you can't divide zero by anything, the slope is 0. We still need the y-intercept for the equation however since the slope is 0 there is no need to put anything else.
Then to find the y-intercept all you have to do is plug in one of the coordinatines into the slope equation to solve, for example, using the point (5,-9):
![(-9) = 5(0) + b](https://tex.z-dn.net/?f=%28-9%29%20%3D%205%280%29%20%2B%20b)
B is the variable for the y-intercept. Also notice how I put 0 as our slope into the equation. Now all you have to do is solve for b. Which you would get b = -9. Since you have your slope and your y-intercept now you just write out your equatoin for the line which is:
y = 0x - 9
**Just write it as
y = -9
Answer:
n=22 or 252=11(22)+10
Step-by-step explanation: 252=11n+10. Start by attempting to isolate the varyable by subracting 10 from both sides--> 242=11n, divide by 11--> 22=n
PROOF 252=11*22+10=242+10=252