What is the slope of the line that passes through the points (2, 8) and (6, 12)?

NEED HELP ASAPPPPPPPPP

Nookie1986 [14]

Answer:

A = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

5 0

3 years ago

Rewrite it as a function and isolate y.

serious [3.7K]

Answer:

f(x) = -5x + 16

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step 1: Define

y + 5x = 16

Step 2: Put into slope-intercept form

Subtract 5x on both sides; y = -5x + 16

Step 3: Rewrite in function notation

f(x) = -5x + 16

5 0

4 years ago

Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

4 years ago

Evaluate each value expression for the given value of x: x-5 , x - =22<br> pls fast

masya89 [10]

Answer:

-18

Step-by-step explanation:

-18

brainlest please

6 0

3 years ago

zhuklara [117]

Step-by-step answer:

Given:

A triangle

Perimeter = 60 cm

longest side = 4* shortest side (x)

Solution:

longest side = 4x

shortest side = x

third (intermediate side = 60 -x -4x = 60-5x

The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle. Hence

x + y > 4x

x + 60-5x > 4x

60 - 4x > 4x

8x < 60

x < 60/8 = 7.5, or

x < 7.5

Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.

Examine the options: both 7 and 5 are both less than 7.5 cm.

40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.

Now also examine cases where 4x is NOT the longest side, in which case we need

4x>=y

or

4x >= 60-5x

9x >=60

x >= 6.67

so x=5 will not qualify, because 4x will no longer be the longest side.

The only valid option is x=7 cm

The side lengths for x=7 and x=5 are, respectively,

(7, 25, 28)

5, 20, 35 (in which case, the longest side is no longer 4x=20, so eliminated)

7 0

3 years ago