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3 years ago

5

the ratio of 7th graders to 8th grader at a school dance is 3 to 2. there are 54 7th graders at a dance. how many 8th graders ar

e at the dance?

1 answer:

Georgia [21]3 years ago

6 0

I just want u to know that u are loved

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the total cost of 4 pens and 7 mechanical pencils is $13.25 the cost of each pencil is $0.75 write an equation that could be use

balu736 [363]

4x+7y=$13.25
4x+ 7($0.75)

7 0

3 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

02.05) simplify i22. (1 point) 1 −1 −i i

olga2289 [7]

I^22 = i^(20 + 2) = i^20 x i^2 = (i^4)^(5) x (i)^2 = 1 x -1 = -1

7 0

3 years ago

If m∠1 = 52°, what is m∠7?

Simora [160]

Answer:

it would be 52 degrees as well because it is a corresponding angle

5 0

3 years ago

Read 2 more answers

The legs of a right triangle measure 70 centimeters and 64 centimeters.

mario62 [17]

Answer:

94.85

Step-by-step explanation:

use pytagorian theorem

c^2=a^2+b^2

5 0

3 years ago