Answer:
We conclude that:
f(a) + 5 = a² + 8a - 5
Step-by-step explanation:
Given
The function is given by
f(x) = x²+8x-10
To determine
f(a)+5
In order to determine f(a)+5, first, we need to determine f(a).
Now substitute x = a in the function f(x) = x²+8x-10
f(a) = (a)² + 8(a) - 10
f(a) = a² + 8a - 10
Thus,
f(a) + 5 = (a² + 8a - 10) + 5
f(a) + 5 = a² + 8a - 5
Therefore, we conclude that:
f(a) + 5 = a² + 8a - 5
17. The letter is J
The letter appears 3 times
18. Lefthanded students = 4 students
<h3>How to determine the factors</h3>
17. We have that 1/4 of the months of the year start with the same letter
It is important to note that:
January, June and July all start with the same letter
The letter is J
The letter appears 3 times
18. Total number of students = 24
5/ 6 are right handed
Right handed students = 24 × 5/ 6 = 4 × 5 = 20 students
Lefthanded students = 24 - righthanded students
Lefthanded students = 24 - 20
Lefthanded students = 4 students
Thus, we can see that the letter that appear in 3 months of the year is J
Learn more about word problems here:
brainly.com/question/13818690
#SPJ1
Answer: D - a rotation 180° about Z’
Answer:
Step-by-step explanation:
GIVEN: A bicycle training wheel has a radius of 
. The bicycle wheel has a radius of 
.
TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.
SOLUTION:
radius of bicycle wheel 
area of bicycle wheel 
putting value,
area of bicycle wheel 
radius of bicycle training wheel 
area of bicycle training wheel
putting value,
area of bicycle wheel 
difference in area of bicycle wheel and bicycle training wheel
hence the training wheel is smaller than regular wheel
Answer:
C.) f(x) = 2x^2 + 4x + 4
Step-by-step explanation:
The equation of the parabola with vertex (h,k) is y=a(−h+x)^2+k.
Thus, the equation of the parabola is y=a(x+1)^2+2.
To find a, use the fact that the parabola passes through the point (2,20): 20=9a+2.
Solving this equation, we get that a=2.
Thus, the equation of the parabola is y=2(x+1)^2+2.
TO STANDARD FORM
= 2*(x^2+2x+1)+2
=(2x^2+4x+2)+2
= 2x^2+4x+2+2
= 2x^2+4x+4
