Answer:
0.0244 (2.44%)
Step-by-step explanation:
defining the event T= the chips passes the tests , then
P(T)= probability that the chip is not defective * probability that it passes the test given that is not defective + probability that the chip is defective * probability that it passes the test given that is defective = 0.80 * 1 + 0.20 * 0.10 = 0.82
for conditional probability we can use the theorem of Bayes. If we define the event D=the chip was defective , then
P(D/T)=P(D∩T)/P(T) = 0.20 * 0.10/0.82= 0.0244 (2.44%)
where
P(D∩T)=probability that the chip is defective and passes the test
P(D/T)=probability that the chip is defective given that it passes the test
320÷((11−9)32(11−9)32) x 8
320÷((352-288)(352-288) x 8
320÷(64 x 64) x 8
320÷4096 x 8
0.078125 x 8
0.625
Answer:0.625
Answer:
The answer to your question is: P = 17 years
Step-by-step explanation:
Data
Parrot = 11 years older than the cat
C = cat age
P = parrot age
P = ? when C = 6
Process
P = C + 11
P = 6 + 11
P = 17 years
I found the dot plots that accompanies this problem.
Based on the plots, the <span>statement that gives is a valid comparison of the number of candies in the bags of the two Brands is:
</span><span>B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.
Dots in Brand B are scattered and whereas dots in Brand A are not and they are more concentrated between 52 to 55 range. </span>
Answer:
c
Step-by-step explanation: