Given that sinx=3/5 where x is an acute angle for cosx
1 answer:
The correct question is
Given that sinx=3/5 where x is an acute angle, what is cosx and tanx<span>?
we know that
</span>since x is acute 0<x<<span>π/2
</span><span>then the trigonometric rations will be positive</span>
sin ²x+cos²x=1------------> cos²x=1-sin²x-------> cos²x=1-(3/5)²----> 1-(9/25)
cos²x=16/25----------> cos x=4/5
the answer part A) is
cos x=4/5
tan x=sin x/cos x
so
tan x=(3/5)/(4/5)---------> tan x=3/4
the answer part B) is
tan x=3/4
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Answer : -89
Explanation: 10 times -7 is -70. -70 minus 19 is -89.
I hope this helps you
1=?.7
?=1/7
Answer:
(x+6i)(x-6i)(x+1)
So the zeroes are 6i, -6i, -1
Step-by-step explanation:
Factor by grouping
h(x) = x^2(x+1) + 36(x+1)
h(x) = (x^2+36)(x+1)
10³ · x = 630
x = ?
10³ = 10 × 10 × 10 = 1,000
630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63
So we have:
10³ · 0.63 = 630
Answer:
option A
Step-by-step explanation:
We can find the standard form by expanding the equation:
y = 3(x-4)^2 - 22
y = 3(x^2 - 8x + 16) - 22
y = 3x^2 - 24x + 48 - 22
y= 3x^2 - 24x + 26
So the correct option is option A
