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levacccp [35]
3 years ago
5

Tom compared \dfrac{2}{12} 12 2 ​ start fraction, 2, divided by, 12, end fraction and \dfrac{7}{6} 6 7 ​ start fraction, 7, divi

ded by, 6, end fraction by first comparing each fraction to \dfrac{1}{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction and 111. Step 1: \dfrac{2}{12} 12 2 ​ start fraction, 2, divided by, 12, end fraction is less than \dfrac{1}{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction. Step 2: \dfrac{7}{6} 6 7 ​ start fraction, 7, divided by, 6, end fraction is less than 111 but more than \dfrac{1}{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction. Step 3: So, \dfrac{2}{12} < \dfrac{7}{6} 12 2 ​ < 6 7 ​ start fraction, 2, divided by, 12, end fraction, is less than, start fraction, 7, divided by, 6, end fraction In which step did Tom make his first mistake?
Mathematics
2 answers:
Alex Ar [27]3 years ago
7 0
It’s 3 so make sure to put that as the answer ok your welcome
soldier1979 [14.2K]3 years ago
6 0

B hope that helps! Btw, it's on khan so put B and it should work!

                                                                                                       

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