Answer:
C) Iron Combines readily with oxygen
Explanation:
When Iron combines readily with oxygen well... it rusts making it a new substance
Answer : The boiling point of the solution is ![101.4^oC](https://tex.z-dn.net/?f=101.4%5EoC)
Explanation :
Formula used for Elevation in boiling point :
![\Delta T_b=i\times k_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3Di%5Ctimes%20k_b%5Ctimes%20m)
or,
![T_b-T^o_b=i\times k_b\times \frac{n_2}{w_1}](https://tex.z-dn.net/?f=T_b-T%5Eo_b%3Di%5Ctimes%20k_b%5Ctimes%20%5Cfrac%7Bn_2%7D%7Bw_1%7D)
where,
= boiling point of solution = ?
= boiling point of water = ![100^oC](https://tex.z-dn.net/?f=100%5EoC)
= boiling point constant of water = ![1.86^oC/m](https://tex.z-dn.net/?f=1.86%5EoC%2Fm)
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= moles of solute (ethylene glycol) = 0.75 mole
= mass of solvent (water) = 1 kg
Now put all the given values in the above formula, we get:
![(T_b-100)^oC=1\times (1.86^oC/m)\times \frac{0.75mole}{1kg}](https://tex.z-dn.net/?f=%28T_b-100%29%5EoC%3D1%5Ctimes%20%281.86%5EoC%2Fm%29%5Ctimes%20%5Cfrac%7B0.75mole%7D%7B1kg%7D)
![T_b=101.4^oC](https://tex.z-dn.net/?f=T_b%3D101.4%5EoC)
Therefore, the boiling point of the solution is ![101.4^oC](https://tex.z-dn.net/?f=101.4%5EoC)
Could u give details about the propanol?
Answer:
![[I_2]=[Br]=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D0.31M)
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:
![I_2+Br_2\rightleftharpoons 2IBr](https://tex.z-dn.net/?f=I_2%2BBr_2%5Crightleftharpoons%202IBr)
Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:
![K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BI_2%5D%5BBr_2%5D%7D%20%5C%5C%5C%5C1.2x10%5E2%3D%5Cfrac%7B%282x%29%5E2%7D%7B%282.0-x%29%5E2%7D)
Thus, we solve for x as show below:
![\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M](https://tex.z-dn.net/?f=%5Csqrt%7B1.2x10%5E2%7D%20%3D%5Csqrt%7B%5Cfrac%7B%282x%29%5E2%7D%7B%282.0-x%29%5E2%7D%7D%20%5C%5C%5C%5C10.95%3D%5Cfrac%7B2x%7D%7B2.0-x%7D%5C%5C%5C%5C21.91-10.95x%3D2x%5C%5C%5C%5C21.91%3D12.95x%5C%5C%5C%5Cx%3D%5Cfrac%7B21.91%7D%7B12.95%7D%20%5C%5C%5C%5Cx%3D1.69M)
Therefore, the concentrations of both bromine and iodine are:
![[I_2]=[Br]=2.0M-1.69M=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D2.0M-1.69M%3D0.31M)
Regards!
1) 2
2) 2
3) there are 2 atoms of hydrogen and 1 atom of oxygen, altogether is 3
4) subscript tells how many atoms of each element are present in the molecule
5) No, it is not balanced because the oxygen atom is not equal on both sides of the reactants and products. This wouldn’t be considered balanced as there are two oxygen atoms in the reactants section and only one oxygen on the products section.
It is:
2 H2 + O2 -> 2 H2O