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Andrei [34K]
4 years ago
5

How does the number of products in a synthesis reaction compare with the number of reactants?

Chemistry
2 answers:
bearhunter [10]4 years ago
5 0
Its a)the no. of products are greater than the no. of reactants
expeople1 [14]4 years ago
5 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Synthesis reaction is defined as the reaction in which two or more substances combine in their elemental state to form a single compound.

The general equation representing this reaction follows:

A+B\rightarrow AB

As, number of reactants in this type of reaction will always be more bacuse a single product is forming in this reaction.

Thus, the correct answer is Option B.

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What s the difference of a mitochondria and a cloroplats
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Mitochondria provides ATP energy in cells after receiving chemical energy. The chloroplast converts energy from the sunlight to chemical energy that is sent to the mitochondria.
3 0
3 years ago
Chloroform has a density of 1.5 g/ml. What the mass of 10.0 ml of Chloroform?
anzhelika [568]
  • Volume=10ml
  • Density=1.5g/ml

\boxed{\sf Density=\dfrac{Mass}{Volume}}

\\ \sf\longmapsto Mass=Density\times Volume

\\ \sf\longmapsto Mass=1.5(10)

\\ \sf\longmapsto Mass=15g

6 0
3 years ago
Help im stuck on this i dont understand
Hunter-Best [27]
A i think. not 100% sure
6 0
3 years ago
Read 2 more answers
Assignment Summary
patriot [66]

Answer:

Whats the question here?

Explanation:

You didn't actually ask a question

4 0
3 years ago
As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po
Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

pH = -log [H_{3}O^{+}]  (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄  CH₃COO⁻ + H₃O⁺    

   1.00 M    

K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}

Solving the above equation for H₃O⁺, we have:    

[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}    (2)    

The dissociation constant is equal to:    

pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}    

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX  ⇄  CH₃COO⁻ +  X⁺  

                                             5.00x10⁻³ M

K_{sp} = [CH_{3}COO^{-}][X^{+}]

[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M

Hence, the pH is:

pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03

Therefore, the pH must be 2.03 to yield a solution in which the concentration of X⁺ is 5.00x10⁻³M.

I hope it helps you!  

6 0
4 years ago
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