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4 years ago

Calculate the amount of heat required for the evaporation of 105.0 g of water at 100.0 c

1 answer:

8 0

To determine the amount of heat needed to evaporate a certain amount of water at its boiling point, we use the equation,

H = m(Hv)

where H is the heat, m is the mass (in grams), and Hv is the latent heat of vaporization. Substituting the known values,

H = (105 g)(540 cal/g)

H = 56700 cal

H = 56.7 kcal

Answer: 56.7 kcal

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(e) A 0.050 mol sample of a hydrocarbon was burned in excess oxygen.

LenKa [72]

The correct answer is 0.15.

We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.

These quantities might be converted to moles by applying the following formula:

amount= mass/ relative atomic mass

Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.

0.05X + x'O2 = 0.15CO2 + 0.2H2O

This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:

1 x + x O2 = 3 co2 + 4 H2O

The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.

Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.

There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.

This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).

To learn more about number of moles of carbon dioxide refer the link:

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6 0

2 years ago

What is Saponification!?

Tom [10]

Answer:

<h3>Saponification is a process that involves conversion of fat, oil or lipid into soap and alcohol by the action of heat in the presence of aqueous alkali. Soaps are salts of fatty acids and fatty acids are monocarboxylic acids that have long carbon chains e.g. sodium palmitate.</h3>

8 0

4 years ago

What volume (in liters, at 703 k and 2.04 atm) of chlorine gas is required to react with 3.39 g of p?

Natali5045456 [20]

The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

2P + 5Cl₂→ 5PCl₅

Therefore, 2 moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

2 moles of P requires 5 moles of chlorine

0.109 moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine

According to ideal gas equation

PV=nRT

2.04 x V = 0.2725 x 0.0821 x 703

V = 0.2725 x 0.0821 x 703 / 2.04

V = 7.71L

Learn more about ideal gas equation here:

brainly.com/question/3637553

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2 years ago

Consider the following balanced equation: 3Ca(NO3)2 + 2AlCl3 --> 2Al(NO3)3 + 3CaCl2. If 610.5 g of calcium nitrate react, wha

____ [38]

Answer:

600g for st product 477.5g for nd product

7 0

3 years ago

Sulfur hexafluoride gas is collected at 26.0 °C in an evacuated flask with a measured volume of 35.0 L. When all the gas has bee

stepan [7]

Answer:

The mass of sulphur hexafluoride collected over water is:

MASS IS 115.28g

NUMBER OF MOLE = 0.04 mole.

Explanation:

Gas constant, R = 0.082 L atm/ mol K

Temperature =26° C = 26 + 273 K =>299 K

Pressure = 0.03 atm

Volume = 35 L

Using the ideal gas equation, we can calculate the number of moles and hence the mass from the mass, molar mass, number of mole relationship.

PV = nRT

Re-arrange by making 'n' the subject of the equation:

n = PV / RT

n = 0.03 * 35 / 0.082 * 299

n = 1.05 / 24.518

n = 0.0428

The number of moles is therefore 0.04 moles

Then we calculate the mass:

Number of moles = mass / molar mass

But before we do that, we must calculate the molar mass of the substance collected over water.

The substance is sulphur hexafluoride and has chemical formula SF6 ( S = 32, F = 19)

Molar mass of SF6 = ( 32 + 19*6)

Molar Mass = 146 g/ mol

Equate the values and then solve for the mass, we get:

Mass = number of moles * molar mass

Mass = 0.04 * 146

Mass = 115.28 g

So therefore, the mass of the sulphur hexafluoride is 115.28g and its number of moles is 0.04 mole.

5 0

3 years ago