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3 years ago

13

What is the midpoint of the line segment with endpoints (-81, 3) and (6,-14) ? 1 totoo

1 answer:

DaniilM [7]3 years ago

7 0

Answer:

Midpoint (xM, yM) = (4, 5)

Step-by-step explanation:

You might be interested in

use the graph to determine the domain and range of the relation and state whether the relation is a function

Alex

Answer:

the domain is {0, 1, 2, 3, 4... to positive infinity}

The range is {-1, -3, 0, -4 and so on}

this is not a function

Step-by-step explanation:

domain is a set of all x values, so just write the x values based on the graph

range is a set of all y values, so just write y values based on the graph

not function because it doesnt satisfy with the vertical line test.

i hop it help u

6 0

3 years ago

Write an expression for the sequence of operations described below. triple v, then subtract 7 from the result Do not simplify an

oee [108]

Given:

The sequence is defined as "triple v, then subtract 7 from the result".

To find:

The expression for the given sequence.

Solution:

Triple v means 3 times of v, i.e., 3v.

So, the result is 3v.

Then subtract 7 from the result. So, the expression for the sequence is

$3v-7$

Therefore, the required expression is $3v-7$ .

6 0

3 years ago

The ratio of boys to girls in a class is 3:4. There are 35 students in the class. How many students are girls?

ASHA 777 [7]

There would be 20 girls

7 0

3 years ago

Read 2 more answers

A water dunking tank at a carnival is in the shape of a right circular cylinder. Its height is 5 feet, and the radius of each ba

bagirrra123 [75]

Answer:

141.37 ft^3

Step-by-step explanation:

No question was asked, but based off of the given information, I will assume you want to know the volume of the circular cylinder.

The volume of a circular cylinder is: v=(π)(r^2)(h)

r=3

h=5

v=(π)(3^2)(5)

v = 141.37

5 0

2 years ago

The amount of time required for an oil and filter change on an automobile is normally distributed with a mean of 45 minutes and

Firdavs [7]

Answer:

1a

$P(39 < X < 48 ) = 0.8767$

1b

95% of all sample means will fall between $40.1 < \mu < 49.9$

1c

$\= x = 41. 795$

2

$n = 25$

Step-by-step explanation:

From the question we are told that

The mean is $n = 45$

The population standard deviation is $\sigma = 10$

The sample size is n = 16

Generally the standard error of the mean is mathematically represented as

$\sigma_{x} = \frac{ \sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 10 }{\sqrt{16 } }$

=> $\sigma_{x} = 2.5$

Generally the probability that the sample mean will be between 39 and 48 minutes is

$P(39 < X < 48 ) = P( \frac{ 39 - 45}{ 2.5} < \frac{X - \mu }{\sigma } < \frac{ 48 - 45}{ 2.5} )$

=> $P(39 < X < 48 ) = P(-2.4 < Z< 1.2 )$

=> $P(39 < X < 48 ) = P( Z< 1.2 ) - P(Z < -2.4)$

From the z table the area under the normal curve to the left corresponding to 1.2 and -2.4 is

=> $P( Z< 1.2 ) = 0.88493$

and

$P( Z< - 2.4 ) = 0.0081975$

So

$P(39 < X < 48 ) = 0.88493 -0.0081975$

=> $P(39 < X < 48 ) = 0.8767$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * 2.5$

=> $E =4.9$

Generally the 95% of all sample means will fall between

$\mu -E < and \mu +E$

=> $45 -4.9\ and \ 45 + 4.9$

Generally the value which 90% of sample means is greater than is mathematically represented

$P( \= X > \= x ) = 0.90$

=> $P( \= X > \= x ) = P( \frac{\= X - \mu }{ \sigma_x} > \frac{\= x -45 }{ 2.5} ) = 0.90$

=> $P( \= X > \= x ) = P( Z > z ) = 0.90$

Generally from the z-table the critical value of 0.90 is

$z = -1.282$

$\frac{\= x -45 }{ 2.5} = -1.282$

=> $\= x = 41. 795$

Considering question 2

Generally we are told that the standard deviation of the mean to be one fifth of the population standard deviation, this is mathematically represented as

$s = \frac{1}{5} \sigma$

Generally the standard deviation of the sample mean is mathematically represented as

$s = \frac{\sigma }{ \sqrt{n} }$

=> $\frac{1}{5} \sigma = \frac{\sigma }{ \sqrt{n} }$

=> $n = 5^2$

=> $n = 25$

5 0

3 years ago