You times it by one and then add the two zeros so your answer is 3,500
Answer:
following are the solution to the given question:
Step-by-step explanation:
It must get everything, or to at least little of it. Unless the shape of even a ball is modified into a square, for example, it simply will not work that form it is used, because it normally can't bounce or roll. There is no issue with other products if modified, for example in an application, as it is quadratic, it will function the same way.
Answer:

Step-by-step explanation:
![\sf Given \ that \ f(x) = 3x + 2 \\\\Put \ x = 2 \\\\f(2) = 3(2) + 2\\\\f(2) = 6+2\\\\\bold{f(2) = 8}\\\\\rule[225]{224}{2}](https://tex.z-dn.net/?f=%5Csf%20Given%20%5C%20that%20%5C%20f%28x%29%20%3D%203x%20%2B%202%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%202%20%5C%5C%5C%5Cf%282%29%20%3D%203%282%29%20%2B%202%5C%5C%5C%5Cf%282%29%20%3D%206%2B2%5C%5C%5C%5C%5Cbold%7Bf%282%29%20%3D%208%7D%5C%5C%5C%5C%5Crule%5B225%5D%7B224%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>