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aliina [53]
3 years ago
6

What is the inequality? A. x < 2 B. x ≤ 2 C. y ≥ 2 D. x > 2

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0

the answer of this inequality is

A. x<2

You might be interested in
|4x-9|=5x Does anybody know the answer to this ?
oksano4ka [1.4K]

|4x-9|=5x

subtract 4 to both sides

and that will give you

|-9|=x then the 9 turns positive because of the brackets

9=X

3 0
3 years ago
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
2 years ago
If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f
nikklg [1K]

The quadratic function given by:


f(x)=a(x-h)^2+k, \ \ \ a\neq 0


is in vertex form. The graph of f is a parabola whose axis is the vertical line x=h and whose vertex is the point (h, k). So:


To translate the graph of a function to the right, left, upward or downward we have:

For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)


By knowing this things, we can solve our problem as follows:


FIRST.

  • Translating <em>11 units to the left:</em>

g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2


  • Then translating<em> 5 units down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5


Since the new function is fatter, the factor we need to multiply the term (x+11)^2 <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.


<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>


SECOND.

  • Translating <em>8 units to the right:</em>

g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2


  • Then translating<em> 1 unit down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1


As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.


<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

7 0
3 years ago
the largest of these five squares has side length 27 units, and each additional square's side length is 2/3 as large as the one
RoseWind [281]

The total area is 1289.41 units².

The total perimeter is 281.32 units.

<h3>What is the total area and perimeter?</h3>

The first step is to determine the side lengths of the other squares:

  • Length of the second square = 2/3 x 27 = 18
  • Length of the third square = 2/3 x18 = 12
  • Length of the fourth square = 2/3 x 12 = 8
  • Length of the fifth square = 2/3 x 8 = 5.33

Area of a square = length²

Perimeter of a square = 4 x length

  • Area of the first square = 27² = 729
  • Area of the second square = 18² = 324
  • Area of the first square = 12² = 144
  • Area of the first square = 8² = 64
  • Area of the first square = 5.33² = 28.41

Total area = sum of the areas of the 5 squares = 1289.41 units²

  • Perimeter of the first square = 4 x 27 = 108 units
  • Perimeter of the second square = 4 x 18 = 72
  • Perimeter of the third square = 4 x 12 = 48
  • Perimeter of the fourth square = 4 x 8 = 32
  • Perimeter of the fifth square = 4 x 5.33 = 21.32

Total perimeter = 281.32 units

To learn how a square, please check: brainly.com/question/9030544

#SPJ1

4 0
2 years ago
Multiply the polynomials. (2x2 + 6x + 6)(3x – 2)
gavmur [86]

Answer:

6x^{3}+16x^{2} +6x-12

Step-by-step explanation:

To calculate the result of that mutiplication you have to firs evaluate the first term of the second function multipying the whole first function, woudl be like this:

(3x)(2x^{2}+6x+6)= 6x^{3}+18x^{2} +18x

Now that you have this, you multiply the second term from the second function to obtain:

(-2)(2x^{2}+6x+6)= -4x^{2}-12x-12

Now you just have to add both results:

6x^{3}+18x^{2} +18x

+       -4x^{2}-12x-12

And the result of the sum would be:

6x^{3}+16x^{2} +6x-12

6 0
3 years ago
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