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klemol [59]
3 years ago
11

What's the missing Vertical angles

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
1.) <1=25°, <2=155°, <4=155°


vichka [17]3 years ago
5 0
So it tells you that 3=25 so then 1 will also equal 25 because vertical angles are congruent then angles 2 and 3 are supplementary so 180- 25= 155 so angle 2 is 155 and angle 4 is 155.
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Answer:

896pi or 2814.9cm^2

Step-by-step explanation:

S=h*r*2pi=(40-2*4)*28/2*2pi=32*14*2pi=896pi=2814.9cm^2

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photoshop1234 [79]

Answer:

Step-by-step explanation:

24

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Simplify (5r^2t)^2(3r^0t^4)
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Answer


75r^4 t^2 + 25r^4 t^6
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Caswell started studying how the number of branches on his tree grows over time. The relationship between the elapsed time ttt,
ipn [44]

Answer:

t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.

Step-by-step explanation:

100 = 5 * 10^(0.3t), solve for t

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0.3t =log(20)

Divide both sides by 0.3:

Multiply the RHS by 10 / 10

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8 0
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What is the domain of F(x) = In(x)?
jekas [21]

Answer as an inequality:  x > 0

Answer in interval notation:  (0, \infty)

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

======================================================

Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is f^{-1}(x) = \log_b(x)

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, \log_b(x) has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of \log_b(x) is x > 0 which in interval notation would be (0, \infty). This is the interval from 0 to infinity, excluding both endpoints.

------------------------

The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

\log_e(x) = \text{Ln}(x)

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.

------------------------

In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.

8 0
3 years ago
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