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3 years ago

10

What is the image point of (0,2) after a translation left 5 units and down 1 unit?

2 answers:

adoni [48]3 years ago

5 0

Answer:

(-5,1)

Step-by-step explanation:

5 units left is x axis and that is going to the negative side, down 1 unit is the y axis.

icang [17]3 years ago

5 0

Answer:

(-5, 1)

Step-by-step explanation:

The equation to solve this would be (x - 5, y - 1), since if you are going left you subtract and if you are going right you would add and up would be add and down would be subtract. Now, you just replace the x and the y with the coords so the equation is now (0 - 5, 2 - 1) which simplifies to (-5, 1) and there's your answer! :)

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Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

dangina [55]

Answer:

$2S+178\ge 2,000,$

$[911,\infty).$

Step-by-step explanation:

Let S be the number of cans that Shane had collected.

Abha had collected 178 more cans than Shane did, then Abha had collected S+178 cans.

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling, this means that

$S+S+178\ge 2,000,\\ \\2S+178\ge 2,000.$

Solve this inequality:

1. Divide it by 2:

$S+89\ge 1,000.$

2. Now

$S\ge 1,000-89,\\ \\S\ge 911.$

The solution set is $[911,\infty).$

6 0

3 years ago

Please help me..............................

myrzilka [38]

Answer:

y = 12

Step-by-step explanation:

∵ m∠ABC = 40

∵ BD ray is the bisector of ∠ABC

∴ m∠ABD = m∠CBD = 20

In 2 Δ BAD and BCD:

∵ m∠BAD = m∠BCD = 90°

∵ m∠ABD = m∠CBD = 20°

∵ BD is a common side in the two triangles

∴ ΔABD congruent to ΔCBD⇒(AAS)

∴ AD = CD

∴ 3y + 6 = 5y - 18

∴ 5y - 3y = 6 + 18

∴ 2y = 24

∴ y = 24/2 = 12

6 0

4 years ago

Jim is enclosing a rectangular garden with 170 feet of fencing. The length of the garden is 10 feet more than twice it’s width,

Darina [25.2K]

Answer:

$1,500\ ft^2$

Step-by-step explanation:

Let

L ----> the length of the rectangular garden in feet

w ---> the width of the rectangular garden in feet

step 1

Find the width

we know that

The perimeter of the rectangular garden is

$P=2(L+W)$

$P=170\ ft$

so

$170=2(L+W)$

Simplify

$85=(L+W)$ ----> equation A

$L=2W+10$ ----> equation B

substitute equation B in equation A and solve for W

$85=(2W+10+W)$

$85-10=3W$

$3W=75$

$W=25\ ft$

Find the value of L

$L=2(25)+10=60\ ft$

step 2

Find the area

we know that

The area of the rectangular garden is

$A=(LW)$

substitute the values

$A=(60)(25)=1,500\ ft^2$

6 0

3 years ago

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d1i1m1o1n [39]

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Zarrin [17]

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