Answer:
You can simplify the problem down by recognizing that you just need to keep track of the integers you've seen in array that your given. You also need to account for edge cases for when the array is empty or the value you get would be greater than your max allowed value. Finally, you need to ensure O(n) complexity, you can't keep looping for every value you come across. This is where the boolean array comes in handy. See below -
public static int solution(int[] A)
{
int min = 1;
int max = 100000;
boolean[] vals = new boolean[max+1];
if(A.length == 0)
return min;
//mark the vals array with the integers we have seen in the A[]
for(int i = 0; i < A.length; i++)
{
if(A[i] < max + 1)
vals[A[i]] = true;
}
//start at our min val and loop until we come across a value we have not seen in A[]
for (int i = 1; i < max; i++)
{
if(vals[i] && min == i)
min++;
else if(!vals[i])
break;
}
if(min > max)
return max;
return min;
}
Answer:
Malware is the shortened form of malicious software. Malware is an umbrella term used to refer to a variety of forms of hostile or intrusive software including Ransom wares, Computer Viruses, Worms, Trojan Horses, Spyware, Adware, Scareware etc.
Answer:
improving the current process before automating it
Answer:
def replace_at_index(str, number):
new = str.replace(str[number], "-")
return new
print(replace_at_index("eggplant", 3))
Explanation:
- Create a function called <em>replace_at_index</em> that takes a string and an integer
- Initialize a new variable called <em>new</em>, that will hold the new string
- Replace the character at given index with dash using <em>replace</em> function, it takes two parameters: the first is the character we want to replace, the second is the new character.
- Return the new string
- Call the function with the required inputs
