She has 10 liters left. Find 4/9 of 18 by multiplying 4/9 and 18. 4/9 of 18 is 8, so she served 8 of the 18, leaving 10 liters.
Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Just to remove ambiguities, the bar over the expression means it's repeating itself to infinity.

notice, the idea being, you multiply it by 10 at some power, so that you move the "recurring decimal" to the other side of the point, and then split it with a digit and "x".
now, you can plug that in your calculator, to check what you get.
Answer:
The correct option is the third: All positive real numbers
Step-by-step explanation:
The domain of this function are all possible values that x can take. If we are talking about the number of miles traveled, these can be as many as the client travels (20.5, 670.23, etc), or zero, if not traveled any. But x can never be less than zero, since it would be absurd for a customer to have traveled -20 miles, for example. Therefore x can take any positive value. The domain of the function is
x> 0
The correct option is the third: All positive real numbers
I'm not sure if it's 10x or 10 times a number