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3 years ago

11

For triangle TRI the following facts are given:

1 answer:

ICE Princess25 [194]3 years ago

5 0

For the answer to the question above,b.Triangle TAN being an image of triangle TRI is smaller than triangle TRI, and so is a contraction.while,
c.) TA/AN = TR/RI3.3/6 = (3.3 + AR)/86(3.3 + AR) = 8 * 3.3 = 26.43.3 + AR = 26.4/6 = 4.4AR = 4.4 - 3.3 = 1.1AR = 1.1
d.) TA/TN = TR/TI3.3/TN = (3.3 + 1.1)/(TN + 1.6)3.3(TN + 1.6) = 4.4TN3.3TN + 5.28 = 4.4TN4.4TN - 3.3TN = 5.281.1TN = 5.28TN = 5.28/1.1 = 4.8TN = 4.8I hope my answer helped you.

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Answer:

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Step-by-step explanation:

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3 years ago

Evaluate 0.53n+5 when n=3

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3 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

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3 years ago

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2 years ago

Help me solving number 22 & 24. Thanks:)

aksik [14]

Answer:

Question 22

x intercept is 7

y intercept is 4

The answer is C

Question 24

x intercept is -4

y intercept is 7

The answer is B

Step-by-step explanation:

x and y intercepts are the points at which the graph meets x and y axes.

x and y intercepts can be found the following way,

y intercept - substitute 0 to x

x intercept - substitute 0 to y

Question 22

$7y=28-4x$

Substitute x=0 to find the y intercept

$7y=28-4*0$

= $7y=28$

= $y=4$

Substitute y=0 to find x intercept

$7*0=28-4x$

= $0=28-4x$

= $4x=28$

= $x=7$

Therefore,

x intercept is 7

y intercept is 4

The answer is C

<u>Question 24</u>

$4y=7x+28$

Substitute x=0 to find the y intercept

$4y=7*0+28$

= $4y=28$

= $y=7$

Substitute y=0 to find x intercept

$4*0=7x+28$

= $0=7x+28$

= $-7x=28$

= $x=-4$

Therefore,

x intercept is -4

y intercept is 7

The answer is B

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2 years ago