Answer:
a) Length= (x+2) and breadth=(x-1) b) 4 m^2 c) R1000
Answer : The Susana swam the fastest.
Step-by-step explanation :
Speed : It is defined as the distance traveled per unit time.
Formula used :

First we have to determine speed of the following persons.
<u>For Tawni :</u>
Distance = 50 m
Time = 40.8 s

The speed of Tawni is, 1.225 m/s
<u>For Pepita :</u>
Distance = 100 m
Time = 60.2 s

The speed of Pepita is, 1.661 m/s
<u>For Susana :</u>
Distance = 200 m
Time = 112.4 s

The speed of Susana is, 1.779 m/s
From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.
Thus, Susana swam the fastest.
Answer:
y = 15.75x + 25 is the linear equation
$88 would be the total cost
Step-by-step explanation:
First, create the equation using y = mx + b, where x is the number of hours:
y = 15.75x + 25 will be the equation, since the charge is $15.75 per hour and the flat fee is $25
There are 4 hours in between 8:30 AM and 12:30 PM, so to find the cost, plug in 4 as x and simplify:
y = 15.75x + 25
Plug in 4 as x:
y = 15.75(4) + 25
y = 63 + 25
y = 88
So, the total cost would be $88
Answer:
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is 
Differences between SRS of 200 and of 600
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.