2 years ago

Solve the following equation algebraically. Represent your answer in simplest radical form, if necessary.

1 answer:

7 0

$x^2 + x = 30\\\\x^2 + x - 30=0\\\\x^2+6x-5x-30=0\\\\x(x+6)-5(x+6)=0\\\\(x+6)(x-5)=0\\\\x+6=0\ \ \ \ \ \ or\ \ \ \ \ \ x-5=0\\\\x=-6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=5$

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My name is Ann [436]

It would be b. the first ratio is
1kL
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2 years ago

Read 2 more answers

What is the inverse of f(x)=3x+6 ?

scZoUnD [109]

Answer:

$\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }$

Step-by-step explanation:

hello,

we can write

$fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}$