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scoray [572]
3 years ago
10

Solve the following equation algebraically. Represent your answer in simplest radical form, if necessary.

Mathematics
1 answer:
maria [59]3 years ago
7 0
x^2 + x = 30\\\\x^2 + x - 30=0\\\\x^2+6x-5x-30=0\\\\x(x+6)-5(x+6)=0\\\\(x+6)(x-5)=0\\\\x+6=0\ \ \ \ \ \ or\ \ \ \  \ \ x-5=0\\\\x=-6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=5
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Someone please help me with this
romanna [79]

Answer:

There are 180 degress in a triangle. so minus the angles given from 180 to find X.

X = 180 - 106 - 30

X = 44 degrees

8 0
3 years ago
BRAINLIEST AND 20 POINTS
Ne4ueva [31]

Answer:

C!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A pilot can fly 2100 miles with the wind in the same time she can fly 1890 miles against the wind. If the speed of the wind is 2
Anna007 [38]

Answer:

475 mph

Step-by-step explanation:

Distance = rate × time

time = distance / rate

If x is the speed of the plane in still air:

2100 / (x + 25) = 1890 / (x − 25)

Cross multiply:

2100 (x − 25) = 1890 (x + 25)

Distribute and solve:

2100x − 52500 = 1890x + 47250

210x = 99750

x = 475

5 0
3 years ago
Harry needs to build a fence around his garden, but first he must figure out the dimensions of his garden. The length of his rec
Lana71 [14]
First, we know L and W are the same number. The in the end the Length is 6 more, therefore we add 6. The equations begins as so
2x+6=27
-6
2x=21
/2
x=10.5
+6
Therefore the Width =10.5 M
The Length = 16.5 M
6 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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