What is the answer to this?
2 answers:
Answer:
Up
Step-by-step explanation:
Y= 1x^2 + 3x + 9
Y= Ax^2 + Bx + C
To determine which way a parabola opens just look at the coefficient (the number) of the x^2 - Always use the coefficient that is beside the x^2
So, if the coefficient A is positive the parabola is opening upward
if the coefficient A is negative the parabola is opening downward
<h3>Up</h3>
<u>How</u><u>?</u><u>?</u>
<em>To</em><em> </em><em>determine</em><em> </em><em>whether</em><em> </em><em>a</em><em> </em><em>parabola</em><em> </em><em>graph</em><em> </em><em>will</em><em> </em><em>go</em><em> </em><em>up</em><em> </em><em>or</em><em> </em><em>down</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>coefficient</em><em> </em><em>of</em><em> </em><em>x</em><em>²</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>quadratic</em><em> </em><em>equation</em><em>.</em> <em>If</em><em> </em><em>the</em><em> </em><em>coefficient</em><em> </em><em>is</em><em> </em><em>positive</em><em> </em><em>then</em><em> </em><em>graph</em><em> </em><em>will</em><em> </em><em>go</em><em> </em><em>up</em> <em> </em><em>and</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>coefficient</em><em> </em><em>is</em><em> </em><em>negative</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>will</em><em> </em><em>go</em><em> </em><em>down</em> <em>.</em> <em>.</em>
<u>In</u><u> </u><u>our</u><u> </u><u>case</u><u>,</u><u> </u><u>The coefficient</u><u> </u><u>of</u><u> </u><u>x</u><u>²</u><u> </u><u>is</u><u> </u><u>+</u><u>1</u><u>,</u><u> </u><u>so</u><u> </u><u>the</u><u> </u><u>parabola</u><u> </u><u>will</u><u> </u><u>open</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>upward</u><u> </u><u>direction</u><u>.</u>
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