All categories

4 years ago

There are two differences between the bank statement and the check register describe each of them

Mathematics

1 answer:

Viefleur [7K]4 years ago

5 0

Step-by-step explanation:

Bank statement would contains the following things as mentioned below:

1) A bank statement is a important document which is sent to the company by the bank to maintain records whereas a check register is maintained by the company which recorded the checks issued in the particular time.

2) A bank statement would contain the deposits and withdrawals details that are made in the past months and the balance at the end of the month whereas a check register would contains name of payee and the reason for the payment etc.

You might be interested in

If the cost of a washing machine is 15480 if the selling price is 17000 what is the profit or lost

Nata [24]

Answer:

1,520

Step-by-step explanation:

6 0

3 years ago

A 28-story hotel building has 18,000 square feet of space for rooms per floor. The average room is 16 ft x 28 ft. How many rooms

Vladimir79 [104]

Answer:

1,120 rooms

Step-by-step explanation:

You need to find out how many hotel rooms are on one floor, and then multiply that by 28. So each room is 16ft x 28ft, which comes out to be 448ft^2. Then to find how many of these rooms go onto one floor, you must divide 18,000 by 448. This equals about 40. So 40 rooms per floor, times 28 floors is: 1,120. And that's your answer! Make sure you understand how we got that. If you have any questions I can help! :)

4 0

4 years ago

What is the value of side x? 4. 5 x =

kolezko [41]

Answer:

Doit your onw

Step-by-step explanation:

kdjdbfdbbswwwk

7 0

3 years ago

Solve for a. a - c = d - r I don't know how to do this since there's no numbers..

Norma-Jean [14]

A = d-r+c
hope i helped!

6 0

4 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago