The exact values of the trigonometric identities cos, csc and tan as required in the task content are; -√41/5, -√41/4 and 4/5 respectively.
<h3>What are the exact values of cos, csc and tan as required in the task content?</h3>
It follows from above that the terminal side of the angle theta as described is on the point with coordinates (-5, -4).
Hence, the points spans 5 units leftwards and r units downwards on x and y axis respectively.
Hence, the length of the line that describes the angle by Pythagoras theorem is;
h = √((-4)² + (-5)²)
h = √41.
Hence, it follows from trigonometric identities that;
Cos (theta) = -5/√41.
Csc (theta) = -√41/4
Tan (theta) = 4/5
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Answer:
same
Step-by-step explanation:
same solution means same slope
Answer:
94
Step-by-step explanation:
Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
Answer:
225 m²
Step-by-step explanation:
If W is the width of the rectangle, and L is the length, then:
60 = 2W + 2L
A = WL
Use the first equation to solve for one of the variables:
30 = W + L
L = 30 − W
Substitute into the second equation:
A = W (30 − W)
A = 30W − W²
This is a parabola, so we can find the vertex using the formula x = -b/(2a).
W = -30 / (2 × -1)
W = 15
Or, we can use calculus:
dA/dW = 30 − 2W
0 = 30 − 2W
W = 15
Solving for L:
L = 30 − W
L = 15
So the maximum area is:
A = WL
A = (15)(15)
A = 225
