First make fractions.
2 5/7 = 19/7
3 4/5 = 19/5
19/7*x=19/5
Multiply 7 to other side (7*19/5=133/5)
Multiply 5 to other side (5*19=95)
95x=133
133 divided by 95 yields 1.4
The answer is 1.4
Answer:
14
Step-by-step explanation:
You can‘t simplify 5/14 because 5 is a prime number. So, now you have to convert the 6/7 to 12/14 to match it up to 5/14. They now have a common denominator of 14.
Hope this helps! :)
Answer:
shaded area = 113.64 cm²
Step-by-step explanation:
To find the shaded area, subtract the area of the circle from the area of the triangle.
Area of a triangle = 1/2 x base x height
⇒ area of triangle = 1/2 x 25 x 21.4 = 267.5 cm²
Area of a circle = 
(where r is the radius)
From inspection, we can see that the diameter of the circle = 14 cm
Therefore, as the diameter = 2r, then r = 14 ÷ 2 = 7 cm
⇒ area of circle = 3.14 x 7² = 153.86 cm²
Shaded area = area of triangle - area of circle
⇒ shaded area = 267.5 - 153.86 = 113.64 cm²
We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
