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Wittaler [7]
3 years ago
14

Can someone help please?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

The slope is the change in Y over the change inX: Using the two points given: (3,9) and (1,3)

The slope is (9-3) / (3-1)

Slope = 6 / 2

Slope = 3


The answer is A.


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The answer is 72 because ice cream has a lot of sugar in it
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3 years ago
A bicycle wheel has a diameter of 24inches. <br> what is the area of the wheel?
goldfiish [28.3K]

Answer:

\large\boxed{A=144\pi\ in^2\approx452.16\ in^2}

Step-by-step explanation:

A diameter is two times longer than a radius. Therefore, if the diameter

d = 24in, then the radius r = (24in) : 2 = 12in.

The formula of an area of a circle:

A=\pi r^2

Substitute:

A=\pi(12)^2=144\pi\ in^2

\pi\approx3.14

Then

A\approx(144)(3.14)=452.16\ in^2

5 0
3 years ago
If g(x)=6/(x-3) find g(5)
alexandr1967 [171]

Answer:

the answer is 3

Step-by-step explanation:

function notation is the way a function is written.

6 0
2 years ago
Given the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dm%28-2x%2B2%29%5E5-n" id="TexFormula1" title="g(x)=m(-2x+2)^5-n"
Alekssandra [29.7K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

The given function g(x) is a continuous function, since, for any x we can find a real value of the function.

A. \frac{d g(x)}{dx} = 5m(-2x + 2)^{4} \times (-2).

Since, m is a constant, which is not equals to 0, the above value of the differentiation of the function, will be negative.

For x = 1, the above value is 0, that is at x =  1, the function has either maximum value, or a minimum value.

B. As per the above information, we have get that for x = 1, \frac{d g(x)}{dx} = 0.

Hence, the function's critical point's x coordinate is x = 1.

The x- coordinate of the given point is not dependent on m or n.

Hence, proved.

4 0
4 years ago
PLEASE HELP!!! I JUST NEED A STEP-BY-STEP!!!!!!
Naya [18.7K]

Answer:

Step-by-step explanation:

=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}x\sec^2(xy)dy\\=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}\sec^2(xy)d(xy)\\=5\displaystyle\int_{0}^{\pi/6}dx\tan(xy)|_{y=0}^{y=2}

=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\

=-\frac{5}{2}\ln{\frac{1}{2}

6 0
2 years ago
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