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bija089 [108]
3 years ago
11

What else would need to be congruent to show that JKL= MNO by AAS?

Mathematics
2 answers:
taurus [48]3 years ago
3 0
Answer: Choice B) Angle L = Angle O

---------------------------------------------------
---------------------------------------------------

If we know that Angle L is congruent to Angle O, then we can use the AAS (angle angle side) congruence property. We have one pair of angles marked by the square marker (angle J and angle M). So they are congruent angles. We have a pair of congruent sides JK = MN = 3. So we're just missing a pair of angles. 

Note: The answer is NOT angle K = angle N because this would mean ASA would be used instead of AAS. The order of the letters is important as it establishes how the sides and angles relate. With ASA, the side is between the angles. With AAS, the side is not between the angles. 

puteri [66]3 years ago
3 0

Answer:

The correct answer is B.

Step-by-step explanation:

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Recall your d = rt, distance = rate * time.

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now, let's notice the trip took a total of 6 hours, thus, if the trip downstream took say "t" hours, then the trip upstream took the slack from 6 and "t", that is, it took "6 - t" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Downstream&90&b+8&t\\
Upstream&90&b-8&6-t
\end{array}
\\\\\\
\begin{cases}
90=t(b+8)\implies \cfrac{90}{b+8}=\boxed{t}\\\\
90=(6-t)(b-8)\\
----------\\
90=\left( 6-\boxed{\cfrac{90}{b+8}} \right)(b-8)
\end{cases}

\bf 90=\left( \cfrac{6b+48-90}{b+8} \right)(b-8)\implies 90=\left( \cfrac{6b-42}{b+8} \right)(b-8)
\\\\\\
90=\cfrac{(6b-42)(b-8)}{b+8}\implies 90(b+8)=(6b-42)(b-8)
\\\\\\
90b+720=6b^2-48b-42b+336\implies 0=6b^2-180b-384
\\\\\\
0=b^2-30b-64\implies 0=(b-32)(b+2)\implies b=
\begin{cases}
\boxed{32}\\
-2
\end{cases}

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