The answer would be y = 1/3x - 1. Your y-intercept is -1 and your slope is 1/3x. I hope this helps love! :)
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I don’t really have an explanation but that’s the answer
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
its 100
Step-by-step explanation:
Let's eliminate x. To achieve this, mult. the 2nd equation by 2, obtaining
-8x + 2y = 10. Now add this result to the first equation:
8x-2y= -10
-8x + 2y = 10
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0
The two equations actually represent the same line. Without an x- or a y-value, we cannot solve for the value of the other variable. There are infinitely many solutions.
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