You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
The following do not have a solution:
• 6x+1=3(2x-4)
• -4(x+3)=4(-x-1)
The value of 4 in the 400 is ten times the value of 4 in the 40's place
10×4,000=40,000 because all u do is add an extra zero everything you multiple something by ten
