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Whitepunk [10]
3 years ago
10

Which of the following are the correct answers??

Mathematics
2 answers:
Amanda [17]3 years ago
6 0
Either B and D. Both seem pretty random lol
kati45 [8]3 years ago
5 0

Answer:

B and D

Step-by-step explanation:

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I need help with point slope formula bad
NISA [10]
Ok so this question:
y + 1 = - ( x - 2 )        (distribute the negative inside the parenthesis)
y + 1 = -x + 2             (substitute the y= -1)
-1 + 1 = -x + 2
0 = -x + 2                   (take two to the other side)
-2 = -x                        (divide the negative away from x)
2 = x

3 0
2 years ago
For the function h(x) defined below, find function f(x) and g(x) so that h(x)=(f^ g)(x) . h(x) = ((x + 2)/x) ^ 3
dem82 [27]

Answer:

Step-by-step explanation:

c

4 0
2 years ago
Help please! asap!
aliya0001 [1]

Answer: 50% or 1/2

Step-by-step explanation:

number of possible combos:

1+1, 1+2, 1+3, 1+4, 1+5, 1+6

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3+1, 3+2, 3+3, 3+4, 3+5, 3+6

4+1, 4+2, 4+3, 4+4, 4+5, 4+6

5+1, 5+2, 5+3, 5+4, 5+5, 5+6

6+1, 6+2, 6+3, 6+4, 6+5, 6+6

number of even sums within combos:

1+1, 1+3, 1+5

2+2, 2+4, 2+6

3+1, 3+3, 3+5

4+2, 4+4, 4+6

5+1, 5+3, 5+5

6+2, 6+4, 6+6

<u>TOTAL combos:</u>

36

<u>TOTAL even sums:</u>

18

so that means 18/36 or 1/2 of the possible combinations has a sum of an even number.

sorry it’s not a table but I literally worked it out while answering so that’s all my work

8 0
2 years ago
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
Solve the equation. Check your answer. If necessary, round to 3 decimal places
Lana71 [14]

Answer:

x ≈ ±20.086/√(t - 1)  

Step-by-step explanation:

ln(t - 1) + ln(x²) = 6

Recall that lnu + lnv = ln(uv). Then  

ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6

Take the natural antilogarithm of each side

(t - 1)x² = e⁶

Divide each side by t - 1

x² = e⁶/(t-1)

Take the square root of each side

x = ±e³/√(t - 1)

x ≈ ±20.086/√(t - 1)

6 0
2 years ago
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