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nata0808 [166]
3 years ago
13

What is the degree of the power function represented in the table?

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

We can plot a graph based on the data from the table given. x represent x-axis and f(x) represent y-axis. From the shape of the graph, we know that it is a quadratic function. Thus, the degree of the power function is 2.

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(9 x 10) + (4 x 0.1)<br> how is this temperature in degrees fahrenheit written as a numeral?
mash [69]

Answer:

360°F

Step-by-step explanation:

When you multiply the numerals in the brackets . The first set of brackets is 90 then the second is 4.0 then multiply them and you will get 360.0°F

3 0
2 years ago
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What is bigger 40% of 210 or 1/4
SOVA2 [1]
40% of 210 is 525, and 1/4 of 210 is 52.5, so the answer is 40% of 210 > 1/4 of 210.
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3 years ago
Jasmine purchases a tablet computer for $233.56. Apps for the tablet cost 99¢ each. If Jasmine had $279 to spend on the tablet a
Leto [7]
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3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
If it takes 1 person 2/3 of a minute to prepare a bag how long would it take 4 peiple to prepare a bag?
Anna11 [10]

Answer:

1/6 of a minute.

Step-by-step explanation:

4 0
3 years ago
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