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3 years ago

12

This expression represents the average cost per game, in dollars, at a bowling alley, where n represents the number of games:

1 answer:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

Average Cost per game for 4 games is:

A) $4.75

Step-by-step explanation:

As the question is not complete, lets complete it first.

At the bowling Alley, shoe rentals cost $3 while a games costs $3. The expression that represents the average costs per game 'c' , in dollars, where n is the number of games, is:

$c=\frac{4n+3}{n}$

To find average cost per game, for 4 games, simpli substitute n=4 into the given equation:

$c=\frac{4n+3}{n}\\c=\frac{4(4)+3}{4}\\c=\frac{16+3}{4}\\c = \frac{19}{4}\\c= 4.75$

So Average Cost per game for 4 games is:

c = 4.75$

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Y_Kistochka [10]

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On the other side of the equation, we'd get

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If it's the second one instead, you can use the same strategy as above:

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allochka39001 [22]

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