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LenKa [72]
3 years ago
12

This expression represents the average cost per game, in dollars, at a bowling alley, where n represents the number of games:

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

Average Cost per game for 4 games is:

A) $4.75

Step-by-step explanation:

As the question is not complete, lets complete it first.

At the bowling Alley, shoe rentals cost $3 while a games costs $3. The expression that represents the average costs per game 'c' , in dollars, where n is the number of games, is:

c=\frac{4n+3}{n}

To find average cost per game, for 4 games, simpli substitute n=4 into the given equation:

c=\frac{4n+3}{n}\\c=\frac{4(4)+3}{4}\\c=\frac{16+3}{4}\\c = \frac{19}{4}\\c= 4.75

So Average Cost per game for 4 games is:

c = 4.75$

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