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tia_tia [17]
3 years ago
8

if there are 486 students at a movies and there are 12 seats in each row about how many rows will the fill.

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

40 and a half

Step-by-step explanation:

Divide 486 by 12.

12 goes into 486 40 whole times.

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NEED HELP 50 POINTS!! WILL MARK BRAINLIEST ANSWER. Find the lengths of all the sides and the measures of the angles.
Sergeeva-Olga [200]

Answer:

Part 1) ∠ABD=23.9°

Part 2) ∠ADB=119.1°

Part 3) AB=506.7 ft

Part 4) ∠BDE=60.9°

Part 5) ∠BED=77.1°

Part 6) DE=239.6 ft

Part 7) BE=312.8 ft

Part 8) ∠BEC=102.9°

Part 9) ∠EBC=36.1°

Step-by-step explanation:

Let

A-----> Zebra house

B ----> Entrance

C ----> Tiger house

D ---> Giraffe house

E ----> Hippo house

see the attached figure with letters to better understand the problem

step 1

In the triangle ABD

Find the measure of angle ABD

Applying the law of sines

sin(37°)/349=sin(ABD)/235

sin(ABD)=235*sin(37°)/349

sin(ABD)=0.4052

∠ABD=arcsin(0.4052)=23.9°

step 2

In the triangle ABD

Find the measure of angle ADB

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

∠ADB+23.9°+37°=180°

∠ADB+23.9°+37°=180°-60.9°

∠ADB=119.1°

step 3

In the triangle ABD

Find the measure of side AB

Applying the law of sines

sin(37°)/349=sin(119.1°)/AB

AB=349*sin(119.1°)/sin(37°)

AB=506.7 ft

step 4

In the triangle BDE

Find the measure of angle BDE

we have

∠BDE+∠ADB=180° ----> by supplementary angles

∠ADB=119.1°

substitute

∠BDE+119.1°=180°

∠BDE=180°-119.1°

∠BDE=60.9°

step 5

In the triangle BDE

Find the measure of angle BED

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

∠BED+60.9°+42°=180°

∠BED=180°-102.9°

∠BED=77.1°

step 6

In the triangle BDE

Find the measure of side DE

Applying the law of sines

sin(77.1°)/349=sin(42°)/DE

DE=349*sin(42°)/sin(77.1°)

DE=239.6 ft

step 7

In the triangle BDE

Find the measure of side BE

Applying the law of sines

sin(77.1°)/349=sin(60.9°)/DE  

BE=349*sin(60.9°)/sin(77.1°)

BE=312.8 ft

step 8

In the triangle BEC

Find the measure of angle BEC

we have

∠BEC+∠BED=180° ----> by supplementary angles

∠BED=77.1°

substitute

∠BEC+77.1°=180°

∠BEC=180°-77.1°

∠BEC=102.9°

step 9

In the triangle BEC

Find the measure of angle EBC

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

∠EBC+102.9°+41°=180°

∠EBC=180°-143.9°

∠EBC=36.1°

3 0
3 years ago
LMN is a right-angle triangle. Angle NLM=90. PQ is parallel to LM. The area of triangle PNQ is 8cm^2. The area of triangle LPQ i
likoan [24]

Answer:

The area of LQM is 48cm^2

Step-by-step explanation:

Given

Area of PNQ = 8

Area of LPQ = 16

See attachment for triangles

The area of PNQ is calculated as:

Area = \frac{1}{2} * PQ * PN

Substitute 8 for Area

8 = \frac{1}{2} * PQ * PN

PQ * PN = 16

The area of LPQ is calculated as:

Area = \frac{1}{2} * PQ * LP

Substitute 16 for Area

16= \frac{1}{2} * PQ * LP

From the attachment:

PN + LP =LN

Make LP the subject

LP = LN -PN

So:

16= \frac{1}{2} * PQ * (LN -PN)

We have:

16= \frac{1}{2} * PQ * (LN -PN) and PQ * PN = 16

Equate both expressions:

\frac{1}{2} * PQ *(LN - PN) = PQ * PN

Divide both sides by PQ

\frac{1}{2} (LN - PN) = PN

Multiply both sides by 2

LN - PN = 2PN

LN= 3PN

Since PNQ is similar to LNM, the following equivalent ratios exist:

\frac{LM}{PQ} = \frac{LN}{PN}

Substitute LN= 3PN

\frac{LM}{PQ} = \frac{3PN}{PN}

\frac{LM}{PQ} = 3

LM = 3PQ

Area of LQM is:

Area = \frac{1}{2} * LM * LP

This gives:

Area = \frac{1}{2} * 3PQ * LP

Area = 3 *\frac{1}{2} *PQ * LP

Recall that:

16= \frac{1}{2} * PQ * LP

So:

Area = 3 *16

Area = 48cm^2

5 0
3 years ago
Joey puts 25% of his allowance into savings each week. If last week he put 10$ in savings, what was his allowance last week?​
Yuri [45]

Answer:

40

Step-by-step explanation:

10=25% so multiply 10 by 4 and cause there is 4 25% in 100

7 0
3 years ago
AOV is a right angle and the ratio AOB: BOC= 2:3 what is the size of angle BOC ?
seraphim [82]
A right angle = 90 degree
BOC = 3/5 of the right angle
= 3/5 x 90
= 54 degree
7 0
3 years ago
Please answer! I'm so close to getting an A in my class, I believe this assignment can get me there, but I'm stuck on this probl
skelet666 [1.2K]
The Answer is d Because x is 2 and y is 1 in both "problems"

4 0
4 years ago
Read 2 more answers
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