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fiasKO [112]
3 years ago
5

_____ have congruent corresponding parts.

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

Two congruent figures

Step-by-step explanation:

Here we have to use the definition of congruent.

Congruent means equal to each other.

Example.

If the two triangles said be congruent, their corresponding angles and corresponding sides are equal.

They will have to same size of the sides and same measure of angles.

Two equal polygons, that is two congruent figures.

Hope this will help you.

Thank you.

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write a equation that is perduliclar to x-3y=3 and passes through the point (5-9).write it in equation slope intersept form​
Anarel [89]

Answer:

The slope of the line is -7/8

When the point (7, –4) is used, the point-slope form of the line is

y+4=(-7/8)(x-7)

The slope-intercept form of the line is y=(-7/8)x+(17/8)

Step-by-step explanation:

Step-by-step explanation:

5 0
3 years ago
Pls help look at the picture
dangina [55]
First answer is 20 .
8 0
3 years ago
Read 2 more answers
A square has an area of 256 square meters. How long is each side?<br><br> _Meters by _ meters
Lorico [155]
Hello!

First, let's write an equation for the problem. 
\sqrt{256}

Now, all you have to do is solve it. 
\sqrt{256} = 16

Each side is 16 meters. 

I hope this helps!
7 0
3 years ago
1. Consider the data set 1,2,3,4,5,6,7,8,9.
ivanzaharov [21]

Answer:  a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

5 0
3 years ago
[ÑL;<br>´lkCuáles son las cosas que pueden medir en fracciones y cuáles en decimales
Vlada [557]

Answer:

Las cosas que se pueden contar (i.e. Contar y clasificar frutas) así como cosas que se pueden dividir se pueden medir en fracciones (i.e. Cortar un pastel), mientras que las cosas que no se pueden contar, de naturaleza no discreta, así como cosas que no se pueden dividir (i.e. Líquidos, material granulado) se pueden medir en decimales.

Step-by-step explanation:

Las cosas que se pueden contar (i.e. Contar y clasificar frutas) así como cosas que se pueden dividir se pueden medir en fracciones (i.e. Cortar un pastel), mientras que las cosas que no se pueden contar, de naturaleza no discreta, así como cosas que no se pueden dividir (i.e. Líquidos, material granulado) se pueden medir en decimales.

8 0
4 years ago
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