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vichka [17]
3 years ago
11

What is the surface area of a square pyramid that has an 8 cm base length and triangular faces that are 14 cm tall? square centi

meters
Mathematics
2 answers:
tatiyna3 years ago
7 0
It's around 296.96 cm^2



good luck
Vedmedyk [2.9K]3 years ago
5 0
Surface Area (S.A.) is the area of all of the faces.
The base is square so its area is: side² = 8 cm x 8 cm = 64 cm²
The faces are triangles so the area of ONE face is: (1/2) x base x height =
(1/2)(8 cm)(14 cm) = 56 cm²

The sum of all of the faces are 64 cm² + 4(56 cm²) = 64 + 224 = 288 cm²

Answer: the surface area of the square pyramid is 288 cm²
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What is the additive inverse of 7/2 ?<br> A) −2/7<br> B) −7/2<br> C) 2/7<br> D) 7/2
snow_lady [41]
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