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vichka [17]
3 years ago
11

What is the surface area of a square pyramid that has an 8 cm base length and triangular faces that are 14 cm tall? square centi

meters
Mathematics
2 answers:
tatiyna3 years ago
7 0
It's around 296.96 cm^2



good luck
Vedmedyk [2.9K]3 years ago
5 0
Surface Area (S.A.) is the area of all of the faces.
The base is square so its area is: side² = 8 cm x 8 cm = 64 cm²
The faces are triangles so the area of ONE face is: (1/2) x base x height =
(1/2)(8 cm)(14 cm) = 56 cm²

The sum of all of the faces are 64 cm² + 4(56 cm²) = 64 + 224 = 288 cm²

Answer: the surface area of the square pyramid is 288 cm²
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3 years ago
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3 years ago
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

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By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

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4 0
3 years ago
Can someone please help? what is the missing length?
Harrizon [31]
31

since A = 1/2 b h, and the A is 279 and the height is 18, we can plug them in and solve for b.
8 0
3 years ago
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