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3 years ago

Can someone help me solve this

Mathematics

1 answer:

alexira [117]3 years ago

8 0

Answer:

Step-by-step explanation:

First=4

Second=1 time

Third=3 turning points

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Please answer this correctly

jolli1 [7]

Answer:

No, because there is just as high of a possibility that the other is biased too.

8 0

3 years ago

What is a system of equations for the following situation? A group of 12 people went to see a movie. The cost to go to the movie

Anna11 [10]

First define the variables:

c = amount of children

a = amount of adults

Next create the equations to satisfy the conditions:

1) Total group is 12 people:

$c+a=12$

2) Total cost is $100 with adults costing $10 and children being $6:

$6c+10a=100$

6 0

3 years ago

Read 2 more answers

What is the area of this triangle A=bh/2 A:17m2 B:30m2 C:60m2 D:120m2

adelina 88 [10]

Base = 5
height = 12

Area = (5*12)/2 = 30 m²

5 0

3 years ago

Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?

Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0 2x - 1 = 0

x = $\frac{3}{4}$ x = $\frac{1}{2}$

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------ $\frac{1}{2}$ ------ $\frac{5}{8}$ ------ $\frac{3}{4}$ ------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!

Test Point $\frac{5}{8}$ : [4( $\frac{5}{8}$ ) - 3][2( $\frac{5}{8}$ ) - 1] = ( - )( + ) = - This does NOT work

Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!

Answer: x ≤ $\frac{1}{2}$ or x ≥ $\frac{3}{4}$

Interval Notation: (-∞, $\frac{1}{2}$ ] U [ $\frac{3}{4}$ , ∞)

Graph: ←------ $\frac{1}{2}$ $\frac{3}{4}$ --------→

5 0

3 years ago

A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (T). Give the sample space describing al

cricket20 [7]

Answer:

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Third toss is heads:

{HHT, HTT, THT, TTT}

First toss is heads, second tails and third heads:

{HTH}

Explanation:

In order to find the sample space we need to write all the possible outcomes from tossing the coin three times.You can start by writting all the possible outcomes for the first toss being a head and finish with all the possible outcomes for the first toss being Tails. The number of elements in the sample space can be found by multiplying the possible outcomes of each toss together, so 2*2*2=8

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For the third toss being heads we will have one restriction this time. Which is that the third toss is Tails. You can take the elements from the sample space where the third element is a tails. In this case, the number of elements can be calculated by multiplying the possible outcomes for only the first two tosses 2*2=4

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For first toss is heads, second tails and third heads there is only one possible way for you to get this outcome so there is only one element to this set.

{HTH}

4 0

3 years ago