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Varvara68 [4.7K]
2 years ago
12

Identify the parent function that can be used to graph the function f(x)= -2x+2

Mathematics
1 answer:
iris [78.8K]2 years ago
8 0

Answer: OPTION C

Step-by-step explanation:

2. The parent function of a linear function is the simplest form of a linear function and this is:

f(x)=x.  Because from this function we can make transformations that allow us to obtain the function f(x) = -2x + 2

3. If you take the parent function and make f(x)-1, then you have:

f(x)-1=x-1 (The function is shifted down 1 unit on the y-axis).

4. Then you make -2f(x), as following:

y=-2(f(x)-1)=-2x+2 (The function is reflected in the y-axis).

5. That is how you obtain the final function.

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Which of the following fractions have repeating decimal representations? Which have terminating decimal representations?
natali 33 [55]

Repeating decimal representation will be 3/13, 7/24. Terminating decimal representation will be 3/16, 4/125.

<h3>What is decimal?</h3>

The accepted method for representing both integer and non-integer numbers is the decimal numeral system. It is the expansion of the Hindu-Arabic numeral system to non-integer values. Decimal notation is the term used to describe the method of representing numbers in the decimal system. The base-10 number system, arguably the most widely used number system, is referred to as decimal. The decimal number system consists of ten single-digit numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. The number following nine is 10.

Here,

Repeating decimal representation,

=3/13, 7/24

Terminating decimal representation,

=3/16, 4/125

3/13 and 7/24 will be repeated in decimal form. The final two decimal places are 3/16 and 4/125.

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7 0
1 year ago
A) how many ways are there to choose 10 players to take the field?
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A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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