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Ronch [10]
3 years ago
10

I WILL GIVE BRAINLIEST. PLEASE HELP RIGHT NOW

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

<em>Answer:  Function A= (0,8)</em>

<em>Function B= (0,2)</em>

<em></em>

<em>{(-4,12),(0,-1),(4,0),(x,y)} =6(4.0),(x,y)</em>

<em></em>

<em></em>

<em>I didn’t do the last one I’m sorry </em>

<em></em>

<em></em>

<em>Step-by-step explanation:</em>

<em></em>

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PLEASE HELP ME
shtirl [24]

Answer:

A ✓5 is the irrational number.

Step-by-step explanation:

Have a good day. :)

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3 years ago
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How do you find the slope using a graph
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The y intercept is seven so you would start by placing a point on (0,7). Then you count Down four points because the slope is a negative number and then count nine points to the right. You would have to keep counting down four points and the right nine points until your line was long enough.
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.Sammie paid $249.99 for a game system and then bought two equally-priced games. If she spent a total of $339.97, what is the pr
bulgar [2K]

Answer: $44.99

Step-by-step explanation:

Let P = equal prices games

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Subtract 249.99 from each side

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3 years ago
There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

Number of orange socks, n(O) = 4

Two socks are picked without replacement.

Now, total number of socks, n(T)=N(P)+n(O)=6+4=10

Probability of picking the first cap as purple cap is given as:

P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

Therefore, the probability that he picked 2 purpled socks is 0.33

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3 years ago
an object is 279.4 centimeters wide. if you divide the object into 10 equal parts, how wide will each part be?
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