Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
Answer:

Step-by-step explanation:
In the Point-Slope Formula [<em>y</em> - <em>y</em>₁ = <em>m</em>(<em>x</em> - <em>x</em>₁)], all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.
I am joyous to assist you anytime.
Remember that to find the vertical asymptotes of rational functions, we just need to set the denominator equal to zero and solve for the variable, in this case

, so lets do it:


As you can see, our rational functions has
2 vertical asymptotes: 
and
90-20 leaves 70 for surfing. since surfing is 5 per hour, 70/5=14 hours she can surf.
Answer:
more information?
Step-by-step explanation:
this question just confuses me a little bit