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Goryan [66]
4 years ago
15

A biologist created the following graph to show the relationship between the temperature of water (x), in degrees Celsius, and t

he number of insect larvae (y) in the water: graph of y equals minus 2 times the square of x plus 20 times x plus 400 What does the peak of the graph represent?

Mathematics
2 answers:
borishaifa [10]4 years ago
7 0

Answer:

The maximum number of larvae occurs when the temperature is 5°C.

Step-by-step explanation:

We are given the function y=-2x^2+20x+400,

where x= temperature of water (in degrees) and y= number of insect larvae in water.

From the graph of the function below, we see that,

The peak or the highest point of the parabola is (5,450).

That is, when x= 5, then the value of y= 450

<em>That is, when the temperature of the water is 5°, then the number of larvae in water is 450.</em>

Hence, the peak of the graph means that,

The maximum number of larvae occurs when the temperature is 5°C.

mario62 [17]4 years ago
6 0
The water has no larvae at -10 degrees Celsius and 20 degrees Celsius
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4 years ago
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In the graphic below, the measure of angle ABC is:
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(Angle ABD) + (Angle ABC) = 180
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8 0
3 years ago
A van travelled at an average speed of 65km/hr from town A. A 35 minutes later a car started from town A ans drove along the sam
kobusy [5.1K]

Answer:

91.6 km/h

Step-by-step explanation:

Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.

Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.

Since the car catches up with the van after it had moved a distance of 130 km,  d = d' = 130 km.

So d = v(t + 0.583)

Substituting d = 130 km and v = 65 km/h, we have

130 km = 65 km/h(t + 0.583)

130 km = (65t + 37.895 )km

subtracting 37.895 from both sides, we have

130 km - 37.895 km = 65t

92.105 = 65t

dividing both sides by 65, we have

t = 92.105/65

= 1.417 h

≅ 1.42 h

Since d = d' = v't,

v' = d'/t

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So, the average speed of the car is 91.6 km/h

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3 years ago
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3 years ago
10 ) (+62) + (+20) + ( -51) =
Vsevolod [243]

Answer: 31

Step-by-step explanation: 62 + 20 - 51 in other words 82 + (-51) or 82 - 51 = 31

6 0
4 years ago
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