Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
a crystal has a regularly repeating arrangement of atoms
Answer: The simplest way is to determine if a strain is mutant is observing morphology, growth rate, double time, etc but it is accurate if you can prove if the strain is deficient in one aminoacid or can't metabolize lactose, etc.
Explanation: A wildtype strain functions normally, for example, can metabolize as a carbon source, glucose, lactose and other sugars, can synthesize all the aminoacids requered for protein synthesis, etc. If a strain suffers a mutation and it is inheritable, the strain become a mutant. Since several mutations can be silent ones, only those that interfere with a process, can be assesed easyly.
For example, if you have several strains and put them in a lactose medium, but some of them cannot growth means that are lactose mutants. Those strains could carry a mutation in genes that encode lactose degrading enzymes or in regulatory genes of the lac operon, etc.
QUESTION NUMBER ONE IS A AND FOR QUESTION NUMBER TWO IT IS B
There are 7 levels of classification for Animals. Kingdom, Phylum, Classes, Order, Families, Genus, and Species.
