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Vedmedyk [2.9K]
3 years ago
13

PLS HELP ME ASAP FOR QUESTION 4!! (MUST SHOW WORK!!!) + LOTS OF POINTS! *brainliest*

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0
-4(2.5y-3.25)-15 1/4=-10y+ Unknown
-10y+13-15.25=-10y+ Unknown
-10y-2.25=-10y+(-2.25), so the answer in the box is -2.25 or -2 1/4. Hope it help!

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Solve 7x/3&lt;2<br> {X I X&lt;6/7}<br> {X I X&gt;6/7}<br> {X I X&lt;-14/3}<br> {X I X&gt;-14/3}
Vladimir79 [104]

Answer:

x<6/7

Step-by-step explanation:

7 0
3 years ago
What does tempature measure
Hoochie [10]

Answer:

Temperature is a measure of the average kinetic energy of the particles in an object.

Step-by-step explanation:

which means its b

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3 years ago
Jimmy invests $7,000 in an account that pays 3% interest compounded semi-annually. What is his balance after 8 years?
Bumek [7]

Answer:

$8882.9

Step-by-step explanation:

A=p(1+(r/n))^nt

Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8

A = 7000(1+(.03/2))^(2×8)

A = 7000 (1+0.015)^16

A = 7000 × 1.015^16

A = $8882.9

7 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
− 0.25(−8+12) PLS HELP I HAVE A TESTTTT
Semmy [17]

Answer: -1

Step-by-step explanation:

− 0.25(−8+12) = -0.25 x 4 =-1

3 0
3 years ago
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