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Slav-nsk [51]
3 years ago
13

How we supposed to find the answer?

Mathematics
2 answers:
Gnoma [55]3 years ago
8 0

Answer:

5^6

Step-by-step explanation:

(5^3)^2

We know that a^b^c = a^(b*c)

5^(3*2)

5^6

Vaselesa [24]3 years ago
5 0

Answer:

5⁶

Step-by-step explanation:

x^{a^{b} }  = xᵃᵇ

on this case:

5^{3^{2} } = 5⁽³⁾⁽²⁾ = 5⁶

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Read 2 more answers
A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find
Shkiper50 [21]

Answer:

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

Step-by-step explanation:

Probability: The ratio of favorable outcomes to the total outcomes.

It is denoted by P.

Probability= \frac{\textrm{favorable outcomes}}{\textrm{Total outcomes}}

Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)

=\frac{\textrm{Total number of blue marbles}}{\textrm{Total number of blue marbles}}

=\frac{7}{15}

The probability of getting a even marble  is P(B)

=\frac{\textrm{The number of even number marbles}}{\textrm{Total number of marbles}}

=\frac{7}{15}

The probability of getting a even numbered blue marble P(A∩B)

=\frac{3}{16}

P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)

=\frac{7}{15} +\frac{7}{15}-\frac{3}{15}

=\frac{11}{15}

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

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3 years ago
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