Answer:
D
Step-by-step explanation:
This is factor by grouping. In factor by grouping, write a quadratic trinomil as 4 terms and group by parenthesis. Then factor by GCF in each pair. If the two parenthesis match, the factoring has worked and the factors will be the GCFs as one and the parenthesis as one other.
The factors here are the GCFs
and -3 as
and the parenthesis (x-5).
You're assuming that this data set represents all of Mrs. Hassaan's pupils. Certain students could be missing from the histogram - for instance, there could be one or two students who missed the test, but for certain reasons will be taking a make-up exam. Their grade would not be recording in this data set, but they still contribute to the class size, and so would be unaccounted for here.
The relationship is that the volume of a cube is equal to one edge length cubed or edge×edge×edge
Answer: 0.9762
Step-by-step explanation:
Let A be the event that days are cloudy and B be the event that days are rainy for January month .
Given : The probability that the days are cloudy = 
The probability that the days are cloudy and rainy = 
Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy = 0.9762
Answer:
Part B: 4 is the constant
Part C: y = 4x
Step-by-step explanation:
y = kx
k = constant
y = 4x
4 is the constant