Write an equation of a line that has a slope of 6 and a x-intercept of 0

Mathematics

1 answer:

Makovka662 [10]2 years ago

6 0

Answer:

y=6x

Step-by-step explanation:

Goes through (0,0)

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Jane draws a line in the coordinate plane that passes through the points (2,3) and (6,9)

timofeeve [1]

Answer:

y=x+1

Step-by-step explanation:

To find the line of the equation, use the slope formula to find the slope.

Slope formula is: y2-y1/x2-x1

9-3/6-2= 3/4

Once you have the slope, use that and one of the coordinates to put the equation in point-slope form.

Point-slope form is: y-y1=m(x-x1), with m representing slope and y1 and x1 representing the x and y coordinates.

y-3=1(x-2)

With the equation in point-slope form, you can now distribute 1 to x-2 and simplify to put it in slope-intercept form.

y-3=1x-2

y=x+1

3 0

2 years ago

Read 2 more answers

The ratio of the circumference of two circles is 3:2.What is the ratio of their area

Nezavi [6.7K]

The ratio of their area is 9/4

<h2>Explanation:</h2>

We use ratios to compares values. In this exercise, we are comparing the circumference of two circles, which is:

$3:2$

and we want to know what is the ratio of their area. Recall that the circumference of a circle is given by:

$C=2\pi r \\ \\ \\ Where: \\ \\ C:Circumference \\ \\ r:Radius \ of \ the \ circle$

If we define:

$C_{1}: \ Circumference \ of \ circle \ 1 \\ \\ C_{2}: \ Circumference \ of \ circle \ 2 \\ \\ r_{1}: \ Radius \ of \ circle \ 1 \\ \\ r_{2}: \ Radius \ of \ circle \ 2$

Then, the ratio of the circumference of two circles is 3:2 is:

$\frac{C_{1}}{C_{2}}=\frac{2\pi r_{1}}{2\pi r_{2}}=\frac{3}{2} \\ \\ \therefore \frac{r_{1}}{r_{2}}=\frac{3}{2}$

The area of a circle is given by:

$A=\pi r^2 \\ \\ A:Area \\ \\ r:Radius$

So the ratio of their area can be found as:

$\frac{A_{1}}{A_{2}}=\frac{\pi r_{1}^2}{\pi r_{2}^2} \\ \\ \\ A_{1}:Area \ of \ circle \ 1 \\ \\ A_{2}:Area \ of \ circle \ 2$

So:

$\frac{A_{1}}{A_{2}}=\frac{r_{1}^2}{r_{2}^2}=\left( \frac{r_{1}}{r_{2}} \right)^2 \\ \\ \frac{A_{1}}{A_{2}}=\left(\frac{3}{2}\right)^2 \\ \\ \boxed{\frac{A_{1}}{A_{2}}=\frac{9}{4}}$