Answer:
yes
Step-by-step explanation:
You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)
(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)
It has to be 438 because any number that is 5 or higher must be rounded up so 438 could be rounded up to 440
Answer:
D: c=(ab-d)/a
Step-by-step explanation:
a(b-c)=d
ab-ac=d
ab=ac+d
ab-d=ac
(ab-d)/a=c
