Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
Answer:
169
Step-by-step explanation:
PEMDAS
Parenthesis first
Add -1 and -3 which is -4
Divide 24 by 6 which is 4
(4-2+5*3*-4÷4)^2
(4-2-15)^2
(2-15)^2
(-13)^2
Which is 169
slope of line=(y2-y1)/(x2-x1)
give is
(x1,y1)=(8,2)
(x2,y2)=(10,2)
therefore slope =(2-2)/(10-8)=0/2=0
Hence
answer
Slope of line=0
The unknown number is 1/2 or 0.5.
ex: 4x+6=8