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Norma-Jean [14]
3 years ago
9

(−5.2)+(−3.8)–{(−1.2)–[(−0.5)–(−0.7)]}

Mathematics
2 answers:
Yakvenalex [24]3 years ago
6 0
The answer is -7.6.

Start with the innermost grouping:

(-5.2)+(-3.8)-{(-1.2)-[(-0.5)-(-0.7)]}

Subtracting a negative is the same as adding a positive:
(-5.2)+(-3.8)-{(-1.2)-[(-0.5+0.7)]}
(-5.2)+(-3.8)-{(-1.2)-[0.2]}

Now start with the next inner grouping:
(-5.2)+(-3.8)-{-1.4}

Again, subtracting a negative is the same as adding a positive:
(-5.2)+(-3.8)+1.4

Add the first two together:
-9.0+1.4

Adding the last two, we get -7.6.
balandron [24]3 years ago
5 0

Answer:-7.6

Step-by-step explanation:

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There are 130 tickets. 30 of these tickets are worth $5 or $ 10. Therefore, 30 of these 130 tickets are worth $5 or greater. Simplying 30 / 130 gives the probability of 3 / 13 or roughly 23%.
6 0
3 years ago
You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 ag
Doss [256]

The probability of winning is 0.44 .

<u>Step-by-step explanation:</u>

Here it's given that , You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 against a quarter of the players (call them type 2), and 0.5 against the remaining quarter of the players (call them type 3). You play a game against a randomly chosen opponent. More precisely :

Probability(type1) = 0.3\\Probability(type2) = 0.4\\Probability(type3) = 0.5\\\\Probability(winning) = w

Now, we choose a random opponent and we need to find probability of winning which is possible as :

<u>1. player chosen from type1</u>

<u>2. player chosen from type2</u>

<u>3. player chosen from type3</u>

Combining all cases we get :

⇒ w = type1(1-type2)(1-type3) + (1-type1)type2(1-type3) + (1-type1)(1-type2)type3

⇒ w = 0.3(0.6)(0.5)+0.7(0.4)(0.5)+0.7(0.5)(0.6)

⇒ w = 0.44

∴ The probability of winning is 0.44 .

8 0
3 years ago
Wilma is 5 times as old as yvonne. in ten years, yvonne's age will be a third of wilma's age. how old are they now?
SVEN [57.7K]

Using a system of equations, it is found that Wilma is 50 years old and Yvonne is 10 years old.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Wilma's age.
  • Variable y: Yvonne's age.

Wilma is 5 times as old as yvonne, hence:

x = 5y.

In ten years, yvonne's age will be a third of wilma's age, hence:

y + 10 = \frac{1}{3}(x + 10)

Since x = 5y:

y + 10 = \frac{1}{3}(x + 10)

y + 10 = \frac{1}{3}(5y + 10)

3y + 30 = 5y + 10

2y = 20.

y = 10.

Then:

x = 5y = 5 x 10 = 50.

Wilma is 50 years old and Yvonne is 10 years old.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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2 years ago
Find the missing length, when you know the perimeter. 9m + 9m + ? + ? = 42m
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Answer:

MISSING LENGTH IS 12 M

Step-by-step explanation:

9+9+ ? + ? = 42m

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7 0
3 years ago
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