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LUCKY_DIMON [66]
3 years ago
14

Please help. Question is in the picture

Mathematics
1 answer:
iragen [17]3 years ago
5 0

Hey,here is the answer to ur question..!
1.BD=AE (given)
2. Ci Is the midpoint of BD and AE (given)
3. AC=EC (Cis the midpoint Of AE)
4. BC=DC (midpoint theorem)
5.angle ACB and angle ECD are vertical angles ( definition of vertical angles)
6. angle ACB=angle ECD (vertical angle theorem)
7.triangle ABC Is congruent to triangle EDC ( SSS criterion rule)
Hope this helps u....!!!

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Square of which numbers are equal to 4?
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The answer would be 2 because a square root has to be the same 2 numbers which is 2 for this example. 2x2=4. Hope this helps! If you have anymore questions please ask me. Stay Safe! And have a good day!

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B4%7D%7Bx%2B4%7D%20-%20%5Cfrac%7B5%7D%7Bx%2B5%3C
Anna11 [10]
[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x +  5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x +  4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x +  4)( x + 5 )] =
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3 years ago
PLS HURRY.<br> Determine whether each statement is true or false?
chubhunter [2.5K]
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3 years ago
Determine the total number of proper subsets of the set of letters from the English alphabet a,b, c, ...,j. The number of proper
Inga [223]
\{a,b,c,\ldots,j\} has ten elements, so any proper subset has at most nine of these elements.

The number of ways of taking any 0\le n\le 9 letters from this set is given by the binomial coefficient,

\dbinom{10}n=\dfrac{10!}{n!(10-n)!}

and in particular, the total number of ways to picking proper subsets is

\displaystyle\sum_{n=0}^9\binom{10}n=\dbinom{10}0+\dbinom{10}1+\cdots+\dbinom{10}9

Without computing each term directly, let's instead use a direct result from the binomial theorem, which says

\displaystyle\sum_{n=0}^N\binom Nna^nb^{N-n}=(a+b)^N

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\displaystyle\sum_{n=0}^N\binom Nn=(1+1)^N=2^N

We can use this to evaluate our sum directly:

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3 years ago
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