Observe it. I would observe the features of it, and research it
Answer:
The correct answer would be <u><em>Garden plants grow better in wet soil than in dry soil.
</em></u>
Scientific hypothesis refers to a proposed or tentative explanation for the occurrence of a particular phenomenon.
Testable hypothesis are those which can be approved or denied on the basis of results of any testing, experience, or data collection.
From the given choices, only fourth hypothesis can be scientifically or experimentally tested.
Same types of plants can be grow in dry and wet soils keeping all other variables constant (such as temperature, light, nutrients et cetera) in order to check the effects of the soil on the plant growth.
Explanation:
hope this helps you.
The answer is rr. In a monohybrid cross, the phenotypic ratio is 3:1 for
dominant trait to recessive trait. Since the ration is 3:1 for round
seeds to wrinkled seeds, we can conclude that round seed is the dominant
trait. Let R be a dominant allele for round seed and r be a recessive
allele for wrinkled seed. The genotypes will be: RR (dominant homozygote
with round seeds), Rr (heterozygote with round seeds), and rr
(recessive homozygote with wrinkled seeds. Thus, only genotype rr is the
genotype of the wrinkled seeds.
Answer:
Keq = 0.00442714664
Explanation:
Glycolysis is the process by which glucose molecule at the end of this process splits into two molecules of pyruvate with the release of energy.
In this question we have to calculate equilibrium concentration of glucose-6-phosphate
This is the first step in Glycolysis
Given Data:
Change in Gibbs free energy = ΔG°’ = +14 kJ/mol = 14000 J/mol
Temperature = T = 37°C
Temperature must be converted into kelvin scale for this question we get
We use formula 37°C + 273.15 = 310.15K
Value of Gas constant = R = 8.3145 J/mol·K (This value is already known)
Equilibrium concentration of glucose-6-phosphate = Keq = ?
Using Formula
<h2>
Keq
= e-ΔG/RT (e is subscript and -ΔG/RT is superscript of e)</h2>
Puting the values we get
Keq = e -14000/8.3145 X 310.15
we get
Keq = e -1683.80 X 310.15
Keq = e -5.42 (As -5.42 is the power of e) we get
Keq = 0.00442714664