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Alex73 [517]
3 years ago
7

A large grouper can weigh 1/3 ton. how much doe a large grouper weigh to the nearest pound?

Mathematics
1 answer:
zvonat [6]3 years ago
7 0
Well, 1 ton = 2000 IBS
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Choose the correct equation for the function of the graph below.
Wittaler [7]

Answer:

Y= 1/2 cos4X (Option 3)

Step-by-step explanation:

It cuts axis at 0.5

8 0
3 years ago
11 The sides of two similar triangle are in a ratio of 5:6. The area of the larger triangle is 108.
Elodia [21]

Answer:

The area of the smaller triangle is 75.

Step-by-step explanation:

Here, the ratio of the sides of the similar triangle are 5 : 6

The area if the larger triangle = 108

let us assume that the area of the smaller triangle = m

By the Theorem:

In two similar triangles, the ratio of the areas of similar triangles is the square of the ratio of their sides.

Similarly, here

[tex](\frac{5}{6}) ^2  = \frac{m}{108}[/tex]

⇒\frac{(5)^2}{(6)^2}   = \frac{m}{108}

or, \frac{25}{36}   = \frac{m}{108}  \implies m = \frac{108 \times 25}{36}  = 75

⇒ m = 75

Hence, the area of the smaller triangle is 75.

6 0
3 years ago
Combine the following sets of terms.
DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

=(3x2+−x2)+(−7x+−3x)+(9)

=2x2+−10x+9

Answer :)

=2x2−10x+9


HOPE THIS HELPS

3 0
3 years ago
A model of a famous statue is 2 1/2 inches tall. The actual statue is 3 1/3 feet tall. What is the ratio of the height of the mo
Gekata [30.6K]

1. A model of a famous statue is 2\dfrac{1}{2} inches tall that is

\dfrac{2\cdot 2+1}{2}=\dfrac{5}{2} in.

2. The actual statue is 3\dfrac{1}{3} feet tall that is

\dfrac{3\cdot 3+1}{3}=\dfrac{10}{3}\ ft=\dfrac{10}{3}\cdot 12=40\ in.

3. The ratio of the height of the model to the height of the actual statue in simplest form is

\dfrac{\dfrac{5}{2}}{40}=\dfrac{5}{2}\cdot \dfrac{1}{40}=\dfrac{1}{16}.

Answer: \dfrac{1}{16}.

4 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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