Answer:
Y= 1/2 cos4X (Option 3)
Step-by-step explanation:
It cuts axis at 0.5
 
        
             
        
        
        
Answer:
The area of the smaller triangle is 75.
Step-by-step explanation:
Here, the ratio of the sides of the similar triangle are 5 : 6
The area if the larger triangle = 108
let us assume that the area of the smaller triangle = m
By the Theorem:
In two similar triangles, the ratio of the areas of similar triangles is the square of the ratio of their sides. 
Similarly, here
 ^2](https://tex.z-dn.net/?f=%5Btex%5D%28%5Cfrac%7B5%7D%7B6%7D%29%20%5E2) = \frac{m}{108}[/tex]
  = \frac{m}{108}[/tex] 
⇒ 
 
or, 
⇒ m = 75
Hence, the area of the smaller triangle is 75.
 
        
             
        
        
        
Let's simplify step-by-step To understand :)
3x2−7x−(x2+3x−9)
Distribute the Negative Sign:
=3x2−7x+−1(x2+3x−9)
=3x2+−7x+−1x2+−1(3x)+(−1)(−9)
=3x2+−7x+−x2+−3x+9
Combine Like Terms:)
=3x2+−7x+−x2+−3x+9
=(3x2+−x2)+(−7x+−3x)+(9)
=2x2+−10x+9
Answer :)
=2x2−10x+9
HOPE THIS HELPS
 
        
             
        
        
        
1. A model of a famous statue is  inches tall that is
 inches tall that is 
 in.
 in.
2. The actual statue is  feet tall that is
 feet tall that is 
 
 
3. The ratio of the height of the model to the height of the actual statue in simplest form is

Answer: 
 
        
             
        
        
        
Answer:

Step-by-step explanation:
we would like to solve the following equation for x:

to do so isolate  to right hand side and change its sign which yields:
 to right hand side and change its sign which yields:

simplify Substraction:

get rid of only x:

simplify addition of the left hand side:

divide both sides by q+p Which yields:

cross multiplication:

distribute:

isolate -pq to the left hand side and change its sign:

rearrange it to standard form:

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so
factor out x:

factor out q:

group:

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

cancel out p from the first equation and q from the second equation which yields:

and we are done!