1. The sum of four and nine times three
<h3>
(4 + 9)×3</h3>
2. eighteen divided by the sum of two and seven
or: 18÷(2+7), or: 18/(2+7)
3. Ten divided by the product of four and five
or: 10÷(4×5), or: 10/(4×5)
4. The Difference of eleven and four times five
<h3> (11 - 4)×5 </h3>
5. The sum of one and two divided by twenty
or: (1+2)÷20, or: (1+2)/20
6. The sum of two and four and six times eight
<h3> (2 + 4 + 6)×8 </h3>
7. The sum of twelve and sixteen divided by the sum of three and four
or: (12+16)÷(3+4), or: (12+16)/(3+4)
8. The difference of twenty-two and six divided by the sum of five and three
or: (22 - 6)÷(5+3), or: (22 - 6)/(5+3)
Answer:
R u on this question still
Step-by-step explanation:
Plz dont take this down
Step-by-step explanation:
Since they have a common denominator the answer is (-5 + 2) / 6 = -3 / 6 = -1/2.
Answers:
Three points that solve the equation: 
The graph is shown in the attached pictures.
NOTE: The first picture is the graph of the equation along with the plotted points, and the second one shows the work for those three points.
Step-by-step explanation:
1. To graph this equation, an easier way to do it would be to convert to slope-intercept form so we can graph knowing the y-intercept and the slope. Do this by isolating the y on the left side like so:
Remember that slope-intercept form is in y = mx + b format, and that m is the slope and b is the y-intercept. With this information, we know that (0, 
) is the y-intercept and 
is the slope of this equation. We can plot the point (0, ) on the graph, and then use the slope of from there to graph other points and form a line. (When I graphed the line, I didn't include these "other points" so it wasn't confusing to locate which points were the three solutions listed.)
2. Points that solve an equation - or solutions - are also points that the line of the equation intersects. So, what we can do is form a table, plug in some x values into the equation, and solve for a y-value. The x and y values will form a point that is on the graph, thus they are solutions. (Please look at the second picture for work and clarification.) After identifying these points, just plot them on the graph and label them (as shown in the first picture).
Answer with explanation:
If you want to Draw a Right Triangle Circumscribed about a circle, Draw a Right Triangle by taking Pythagorean Triplet.
Now, Draw Perpendicular Bisector of any of two sides.The Point where the two bisectors meet is center of the circle.
To find the center we have used the theorem, line from the mid point of the chord passes through the center of the circle.
From the center , that is at the point where the perpendicular bisectors meet,draw a circle Passing through three vertices of Right Triangle.
