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2 years ago

Why is protein synthesis necessary for cell division to occur

1 answer:

5 0

Protein synthesis is the process whereby DNA encodes for the production of amino acids and proteins. This process can be divided into two parts: Transcription and Translation.

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Which of the following is not a domain?

enyata [817]

C Is the correct answer

4 0

3 years ago

Two true-breeding stocks of pea plants are crossed. one parent has red, axial flowers and theother has white, terminal flowers;

xxTIMURxx [149]

This is a typical case of a dihybrid cross.
From the phenotype of the offspring, we can conclude that the gene for the red color of the flower and the gene for the axial position of the flower are dominant.
Since we know that the ratio of phenotypes in a dihybrid cross of independently inherited alleles is
9(dominant for both traits)
3(dominant for one trait, recessive for the other)
3(dominant for the second trait, recessive for the other)
1(recessive for both traits)
we can expect 3/16 of the f2 generation to be dominamt for one trait and recessive for the other (red, terminal flowers), or to be precise 190 individuals.

7 0

3 years ago

If you drop a metal paperclip into a cup of water, it will sink to the bottom, however with practice, you can gently place a met

WARRIOR [948]

Answer:

The answer is A because the water has strong surface tension, I didn't know why but I know it's surface tension holding it up so it has to be A

7 0

2 years ago

Read 2 more answers

Humans cultivate plants that house bacteria in soil to convert ammonia and ammonium ions to ___________________.

Pepsi [2]

Answer:

Humans cultivate plants that house bacteria in soil to convert ammonia and ammonium ions to nitrate

Explanation:

8 0

2 years ago

In hamsters, we can examine the genes for coat color and eye color which are linked:B = brown coat, b = white coat, G = green ey

Inessa [10]

Answer:

10.2 cM

Explanation:

Given,

pure breeding parent 1 : BBgg = brown coat and pink eyes

pure breeding parent 2 : bbGG = white coat and green eyes

BBGG X bbgg = F1 = BbGg ( All are brown with green eyes )

When F1 progeny is test crossed with white coat and pink eyes hamster:

BbGg X BbGg = F2 =

brown, pink eyes = 99 = parental

white, green eyes = 103 = parental

brown, green eyes = 12 = recombinant

white, pink eyes = 11 = recombinant

Recombination frequency =

(total number of recombinants / total progeny ) * 100

= [( 11 + 12 ) / ( 99 + 103 + 12 + 11 )] * 100 = (23/225)*100 = 0.102 * 100 = 10.2 %

1 % recombination frequency = 1 cM distance between genes

Hence, the distance between B and G gene is 10.2 cM

4 0

3 years ago