The sodium amytal test involves the injection of a small amount of sodium amytal into the carotid artery on one side of the neck. This injection anesthetizes the hemisphere on that side for a few minutes.
A method that involves injecting a small amount of a barbiturate into the carotid artery on one side of the head to assess hemispheric functions, usually memory and language. The cerebral hemisphere that was injected selectively becomes impaired for 10 to 15 minutes during this operation.
Various cognitive tests are given while each hemisphere is seperately anaesthetized; deficiencies on these tasks imply that these functions are represented in the anaesthetized hemisphere. Prior to a temporal lobectomy, the Wada test may be utilised in cases with severe and uncontrollable epilepsy. Also known as the Wada technique, intracarotid sodium Amytal test (ISA), Wada dominance test, and intracarotid amobarbital procedure.
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It may be 166, but you may want to check my math
The second one would be my answer but also an answer that is not up there is that during an experiment when repeating the trials you might have to set up a new hypothesis every time and have to review the data several different times because of different results from each trial
hope this helps if not just let me know
Answer:
the first is mostly false but somewhat tru the second is true and the third is true
Explanation:
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
