Answer:
The first person to observe cells was Robert Hooke. Hooke was an English scientist. He used a compound microscope to look at thin slices of cork.
Explanation:
Sorry if I am wrong let me know if I am.
I think it’s sperm for your question
Answer:
True
Explanation:
ATP – or Adenosine Triphosphate – is the primary energy carrier in all living organisms on earth. Microorganisms capture and store energy metabolized from food and light sources in the form of ATP.
When the cell requires energy, ATP is broken down through hydrolysis. The high energy bond is broken and a phosphoryl group is removed. The energy released from this process is used to drive various cellular processes. ATP is constantly formed and broken down as it participates in biological reactions and it is central to the health and growth of all life. Without it, cells could not transfer energy from one location to another, making it impossible for organisms to grow and reproduce.
ATP is a nucleotide that consists of three main structures: the nitrogenous base, adenine; the sugar, ribose; and a chain of three phosphate groups bound to ribose.
Answer:
climatologists
Explanation:
they are the ones studying the effects of global warming on earth's climate
Answer:
CH₄ is the excess reagent and SO₄²⁻ is the limiting reagent.
0.040 g
Explanation:
Step 1: Write the balanced reaction for the methane anaerobic oxidation
CH₄ + SO₄²⁻ ⇒ S²⁻ + CO₂ + 2 H₂O
Step 2: Establish the theoretical mass ratio between the reactants
According to the balanced equation, the theoretical mass ratio of CH₄ to SO₄²⁻ is 16.04:96.06 = 0.1670:1
Step 3: Establish the experimental mass ratio between the reactants
50 mg (0.050 g) of CH₄ react with 60 mg (0.060 g) of SO₄²⁻. The experimental mass ratio of CH₄ to SO₄²⁻ is 0.050:0.060 = 0.83:1
Comparing both mass ratios, we can deduce that CH₄ is the excess reagent and SO₄²⁻ is the limiting reagent.
Step 4: Calculate the mass excess of CH₄
The mass of CH₄ that reacts with 0.060 g of SO₄²⁻ is:
0.060 g SO₄²⁻ 16.04 g CH₄/96.06 g SO₄²⁻ = 0.010 g CH₄
The mass excess of CH₄ is:
0.050 g - 0.010 g = 0.040 g
